The particle has constant acceleration according to
Its velocity at time is
Then the particle has position at time according to
At at the point (3, 6, 9), i.e. when , it has speed 8, so that
We know that at some time , the particle is at the point (5, 2, 7), which tells us
and in particular we see that
and
Then
That is, there are two possible initial velocities for which the particle can travel between (3, 6, 9) and (5, 2, 7) with the given acceleration vector and given that it starts with a speed of 8. Then there are two possible solutions for its position vector; one of them is
Explanation:
Formula for finding power : 1/f
Substitution of values:
1 /13.3 = 0.07518 cm
Please mark it as Brainliest!
To solve the problem it is necessary to take into account the concepts related to frequency depending on the wavelength and the speed of light.
By definition we know that the frequency is equivalent to,
where,
c= Speed of light
While the wavelength is equal to,
Where,
L = Length
n = Number of antinodes/nodes
PART A) For the first part we have that our wavelength is 110MHz, therefore
Therefore the distance between the nodal planes is 1.36m
PART B) For this part we need to find the Length through the number of nodes (8) and the wavelength, that is,
Therefore the length of the cavity is 10.90m