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san4es73 [151]
3 years ago
9

Please have a look at the image!

Physics
1 answer:
EastWind [94]3 years ago
3 0
Nice problem!

Look. At point A the road changes from a straight line to a circular line, then the motion changes from  rectilinear to circular motion. So at that point, there is a sudden change in the acceleration, which for sure the passengers feel.

At point B, the circular motion changes from anticlockwise to clockwise, then there is another sudden change in the acceleration.

At point C, the road changes from circular to straihgt line, then the motion changes from rectilinear to circular, which produces a new sudeen change in acceleration.

Then the answeer is the last option, at points A, B and C.
You might be interested in
if the resistance of a car headlight is 15 ohm and the current through it is 0.60, what is the voltage across the headlight?
Strike441 [17]

Answer:

9 volts (assuming 0.60 is in Amperes)

Explanation:

Recall that Ohms law can be expressed as

V = IR, where

V = voltage,

I = current (given as 0.6. I'm going to assume that the units is Amperes because it is not given)

R = resistance (given as 15 ohm)

substituting the above values into the formula

V = IR

V = (0.6)(15)

V = 9 Volts

4 0
3 years ago
Read 2 more answers
A long copper wire of radius 0.321 mm has a linear charge density of 0.100 μC/m. Find the electric field at a point 5.00 cm from
krek1111 [17]

Answer:

E=35921.96N/C

Explanation:

From the question we are told that:

Radius r=0.321mm

Charge Density \mu=0.100

Distance d= 5.00 cm

Generally the equation for electric field is mathematically given by

E=\frac{mu}{2\pi E_0r}

E=\frac{0.100*10^{-6}}{2*3.142*8.86*10^{-12}*5*10^{-2}}

E=35921.96N/C

4 0
3 years ago
65 POINTS! PLEASE ANSWER EVERY QUESTION! NEED HELP ASAP!
otez555 [7]
Maybe you can split up the questions. I will try to answer your first question.

1. In an elastic collision, momentum is conserved. The momentum before the collision is equal to the momentum after the collision. This is a consequence of Newton's 3rd law. (Action = Reaction)

2. Momentum: p = m₁v₁ + m₂v₂

m₁ mass of ball A
v₁ velocity of ball A
m₂ mass of ball B
v₂ velocity of ball B

Momentum before the collision:
p = 2*9 + 3*(-6) = 18 - 18 = 0

Momentum after the collision:
p = 2*(-9) + 3*6 = -18 + 18 = 0

3: mv + m(-v) = m(-v) + m(v)
the velocities would reverse.

4.This question is not factual since the energy of an elastic collision must also be conserved. The final velocities should be: v₁ = -1 m/s and v₂ = 5 m/s. That said assuming the given velocities were correct:
before collision
p = 10*3 + 5*(-3) = 30 - 15 = 15
after collision:
p = 10*(-2) + 5 * v₂ = 15
v₂ = 7

5.You figure out.



3 0
3 years ago
There you guys go no one take the points or youll get banned step juice world kid
jasenka [17]

Answer:

thxs ace

Explanation:

6 0
3 years ago
Read 2 more answers
The electroscope is an apparatus used to detect electric charge. The electroscope consists of a plate, a support and a free to r
Marat540 [252]

Answer:

Positive

Explanation:

The leaves will diverge further: The positive charge on the leaves has increased further. This occurs when positive charge is produced on the leaves by the charged object. This is quite possible only when the object is positively charged.

4 0
3 years ago
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