All categories

2 years ago

What are the things to consider in classifying the different kinds of mixture?

Chemistry

1 answer:

algol132 years ago

4 0

Answer:

Whether the mixture can be separated

You might be interested in

Which of the following changes in the state of a substance results in an increase in the entropy?

AlekseyPX

Answer:

the correct answer is

D. solid to liquid

7 0

2 years ago

Read 2 more answers

SC1^2 iconic or covalent

yulyashka [42]

Answer:

Covalent

Explanation:

Sulfur and Chlorine are non metals so if they combine, they become covalent.

4 0

2 years ago

How are elements similar to those in the same group on the periodic table

enot [183]

Answer:

All the members of a group of elements have the same number of valence electrons and similar chemical properties.

Explanation:

The vertical columns on the periodic table are called groups or families because of their similar chemical behavior.

5 0

2 years ago

What factors affect the vegetation of a place?

ale4655 [162]

Answer:

climate ,soils,nature of the surface and man

7 0

2 years ago

A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe

Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: $V_{1}$ = 571 mL, $T_{1} = 26^{o}C$

(a) $T_{2} = 5^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL$

(b) $T_{2} = 95^{o}F$

Convert degree Fahrenheit into degree Cesius as follows.

$(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL$

(c) $T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL$

8 0

2 years ago