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2 years ago

THE NUMERICAL RATIO OF DISPLACEMENT TO DISTANCE IS:

Physics

1 answer:

Tamiku [17]2 years ago

7 0

There's no general rule.

Displacement is the length of a straight line from start to finish, and distance is how far you actually traveled from start to finish.

The only thing we really know is that distance can never be shorter than displacement. So I guess the answer is:

<em>The numerical ratio of displacement to distance is always 1 or less</em>.

(But it has to be written ALL IN CAPITALS.)

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3 years ago

A steel wire in a piano has a length of 0.680 m and a mass of 4.600 ✕ 10⁻³ kg. To what tension must this wire be stretched so th

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$f = \frac{1}{2L} \sqrt{\frac{TL}{m} } \\261.6 = \frac{1}{2(0.680)} \sqrt{\frac{T(0.80)}{0.0046} }\\(2) (0.680) (261.6) = \sqrt{\frac{T(0.80)}{0.0046} }\\355.8 = \sqrt{\frac{T(0.80)}{0.0046} }\\355.8^{2} = \frac{T(0.80)}{0.0046}\\T = \frac{(355.8^{2}(0.0046))}{0.80} \\T = 728 N$

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2 years ago

THE NUMERICAL RATIO OF DISPLACEMENT TO DISTANCE IS:​

THE NUMERICAL RATIO OF DISPLACEMENT TO DISTANCE IS: