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Wewaii [24]
3 years ago
14

A specialist who treats skin conditions and diseases is a

Physics
1 answer:
s2008m [1.1K]3 years ago
5 0
A doctor who specializes in the area of skin health is a dermatologist
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If the light wave has a wavelength of 10m what would be its velocity
s2008m [1.1K]

If this case could ever happen, the speed would follow from this formula:

v = f \cdot \lambda

with f the frequency and lambda the wavelength. We are give a wavelength of 10m. The frequencies of the visible light can range between 400 to about 790 Terahertz, so let us pick a middle point of 600 THz ("green-ish") as a "representative."

v = 600THz\cdot 10m = 6\cdot 10^{14} \frac{1}{s}\cdot 10 m = 6\cdot10^{15}\frac{m}{s}

The speed of such a wave would have to be 6e+15 m/s (which would be 7 orders of magnitude higher than the universal speed of light constant)

7 0
3 years ago
Read 2 more answers
a car traveling at 30m/s notices an accident about 65m up the road. The car's brakes are capable of decelerating at a rate of 6.
uysha [10]
Yes because you would have at least 3 car spaces
4 0
3 years ago
Can someone plz help me with this
Elena-2011 [213]
1st Law: Objects that are in motion tend to stay in motion. This motion can change with external forces. 

<span>If you were to stop pedaling on bike while in motion, you will notice that you will keep moving. This is because a moving body (you) has inertia. If there wasn't any friction between the tires and the ground, between the axles and wheel, any air resistance, or any other force that acts against you, then you could be coasting indefinitely! </span>

<span>2nd Law: Force is equal to the mass times acceleration. </span>

<span>When you pedal, you are applying a force onto the pedal. This force is then translated through tension to apply torque onto the wheel. Turning the wheel will make you accelerate in the lateral direction. </span>

<span>3rd Law: For every action, there is an equal and opposite reaction. </span>

<span>Without this, you could pedal and pedal, but you will be not go anywhere! It is essentially the friction between the tires and the ground that propels you forward. If the ground did not apply to the tire the same amount of force that the tire was applying to the ground, the tire would not "catch" and no friction would be applied. And if there was no third law, the weight of you and your bike would "sink" into the ground because the ground would not be applying a normal force back onto you.

hope this helps and if you have any questions just hmu and ask :)</span>
3 0
3 years ago
How much faster will a car be going if it accelerates at 1 m/s/s for a total of 60 seconds.
guajiro [1.7K]

Answer:

Vf = 60 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f}= v_{i}+(a*t)

where:

Vf = final velocity [m/s]

Vi = initial velocity = 0

a = acceleration = 1 [m/s^2]

t = time = 60 [m]

Now replacing:

Vf = 0 + (1*60)

Vf = 60 [m/s]

4 0
3 years ago
A 930-kg sports car collides into the rear end of a 2000-kg SUV stopped at a red light. The bumpers lock, the brakes are locked,
bekas [8.4K]

Answer:2.103 m/s

Explanation:

Given

mass of sports car m=930\ kg

mass of SUV M=2000\ kg

Suppose u is the velocity if sports car before collision

Conserving momentum we get

mu=(M+m)v

v=\dfrac{2000+930}{930}\times u

v=3.15\cdot u

After collision the combined mass drag 2.8 m and finally stops

From work energy theorem work done by friction is equal to change in kinetic energy of the  combined mass system

\frac{1}{2}(M+m)v^2=\mu (M+m)gx

where \mu =\text{coefficient of friction}

x=\text{drag distance}

v=\sqrt{2\mu gx}

v=\sqrt{2\times 0.8\times 9.8\times 2.8}

v=6.626\ m/s

Initial velocity u=\frac{6.626}{3.15}

u=2.103\ m/s

6 0
3 years ago
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