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3 years ago

A specialist who treats skin conditions and diseases is a

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s2008m [1.1K]3 years ago

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A doctor who specializes in the area of skin health is a dermatologist

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If wavelength and speed of a wave are 4 m and 332 m/s respectively, calculate its frequency

Furkat [3]

Explanation:

Given 

wavelength = 4 m

speed = 332 m/s

frequency = ?

We know we have the formula 

wavelength = speed / frequency 

4 = 332 / frequency 

frequency = 332/4

Therefore frequency is 83 Hertz .

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3 years ago

If we increase the force applied to an object and all other factors remain the same that amount of work will

worty [1.4K]

Hello there.

If we increase the force applied to an object and all other factors remain the same that amount of work will

C. Increase

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Ymorist [56]

Do you need help with all of them

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I will Mark as the brainliest answer

Kobotan [32]

Answer: looks good

Explanation:

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Two neutron stars are separated by a distance of 1.0 x 1012 m. They each have a mass of 1.0 x 1028 kg and a radius of 1.0 x 103

son4ous [18]

To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.

Gravitational potential energy can be defined as

$PE = -\frac{GMm}{R}$

As M=m, then

$PE = -\frac{Gm^2}{R}$

Where,

m = Mass

G =Gravitational Universal Constant

R = Distance /Radius

PART A) As half its initial value is u'=2u, then

$U = -\frac{2Gm^2}{R}$

$dU = -\frac{2Gm^2}{R}$

$dKE = -dU$

Therefore replacing we have that,

$\frac{1}{2}mv^2 =\frac{Gm^2}{2R}$

Re-arrange to find v,

$v= \sqrt{\frac{Gm}{R}}$

$v = \sqrt{\frac{6.67*10^{-11}*1*10^{28}}{1*10^{12}}}$

$v = 816.7m/s$

Therefore the velocity when the separation has decreased to one-half its initial value is 816m/s

PART B) With a final separation distance of 2r, we have that

$2r = 2*10^3m$

Therefore

$dU = Gm^2(\frac{1}{R}-\frac{1}{2r})$

$v = \sqrt{Gm(\frac{1}{2r}-\frac{1}{R})}$

$v = \sqrt{6.67*10^{-11}*10^{28}(\frac{1}{2*10^3}-\frac{1}{10^{12}})}$

$v = 1.83*10^7m/s$

Therefore the velocity when they are about to collide is $1.83*10^7m/s$

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3 years ago