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mars1129 [50]
4 years ago
7

Consider successive ionizations of the element Ca. Which ionization would you expect have the largest increase relative to the p

revious one?A) 2ndB) 3rdC) 4thD) 5thE) 6th
Chemistry
1 answer:
nexus9112 [7]4 years ago
5 0

Answer:

B) 3rd

Explanation:

The 3rd ionization energy represents the removal of electrons from a filled core shell.

The electron configuration of calcium is [Ar]4s^2. Hence after the removal of the second electron from the 4s^2 orbital, a lot of energy is required to remove an electron from the next completely filled core shell. This is the highest successive jump in ionization energy. The other options in the question deal with electrons found on the same shell.

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Answer : The value of \Delta E for this reaction is 36.18 kJ

Explanation :

First law of thermodynamic : It states that the energy can not be created or destroyed, it can only change or transfer from one state to another state.

As per first law of thermodynamic,

\Delta E=q+w

where,

\Delta E = internal energy  of the system

q = heat added or rejected by the system

w = work done

As we are given that:

q = 38.65 kJ

w = -2.47 kJ (system work done on surrounding)

Now put all the given values in the above expression, we get:

\Delta E=38.65kJ+(-2.47kJ)

\Delta E=36.18kJ

Therefore, the value of \Delta E for this reaction is 36.18 kJ

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A 32.4 L gas sample at STP is compressed to a volume of 28.4 L, and the temperature is increased to 352 K. What is the new press
Sindrei [870]

Answer:

1.47 atm

Explanation:

Step 1: Given data

  • Initial volume (V₁): 32.4 L
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  • Final volume (V₂): 28.4 L
  • Final pressure (P₂): ?
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Step 2: Calculate the final pressure of the gas

We can calculate the final pressure of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

P₂ = P₁ × V₁ × T₂ / T₁ × V₂

P₂ = 1 atm × 32.4 L × 352 K / 273 K × 28.4 L = 1.47 atm

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