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mars1129 [50]
4 years ago
7

Consider successive ionizations of the element Ca. Which ionization would you expect have the largest increase relative to the p

revious one?A) 2ndB) 3rdC) 4thD) 5thE) 6th
Chemistry
1 answer:
nexus9112 [7]4 years ago
5 0

Answer:

B) 3rd

Explanation:

The 3rd ionization energy represents the removal of electrons from a filled core shell.

The electron configuration of calcium is [Ar]4s^2. Hence after the removal of the second electron from the 4s^2 orbital, a lot of energy is required to remove an electron from the next completely filled core shell. This is the highest successive jump in ionization energy. The other options in the question deal with electrons found on the same shell.

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At room temperature,table salt is a solid and mercury is a liquid.what conclusion can you draw about the melting points of these
never [62]
That table salt has a high melting point and mercury's melting point is low.
4 0
3 years ago
Read 2 more answers
After a tree is cut down with a chainsaw, it is impossible to put the tiny wood chips back together
Shtirlitz [24]

Answer:

No, because even if you cut the tree into small pieces it’s still a tree.

Explanation:

4 0
3 years ago
Read 2 more answers
Check all that apply.
White raven [17]

Answer:

4 for C in CH4

+4 for C in CO2

-2 for O in all substances

+1 for H in both CH4 and H2O

option 1,2,3 and 4 are correct. Option 5 is not correct

Explanation:

Step 1: Data given

Oxidation number of H = +1

Oxidation number of O = -2

Step 2: The balanced equation

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Step 3: The oxidation numbers

-4 for C in CH4

 ⇒ Oxidation number of H = +1

    ⇒ 4x +1 = +4

C has an oxidation number of -4

This is correct.

+4 for C in CO2

 ⇒ Oxidation number of O = -2

    ⇒ 2x -2 = -4

C has an oxidation number of +4

This is correct.

-2 for O in all substances

⇒ this is correct, the oxidation number of O is always -2 (except in H2O2 and Na2O2)

This is correct.

+1 for H in both CH4 and H2O

⇒ this is correct, the oxidation number of H is always +1 (except in metal hydrides).

This is correct.

+4 for O in H2O

 ⇒ Oxidation number of H = +1

    ⇒ 2x +1 = +2

The oxidation number of O is -2

This is not correct

5 0
3 years ago
How many grams of NO are required to produce 145 g of N2 in the following reaction?
V125BC [204]

Answer:

b. 186 g

Explanation:

Step 1: Write the balanced equation.

4 NH₃(g) + 6 NO(g) → 5 N₂(g) + 6 H₂O(l)

Step 2: Calculate the moles corresponding to 145 g of N₂

The molar mass of nitrogen is 28.01 g/mol.

145g \times \frac{1mol}{28.01 g} =5.18 mol

Step 3: Calculate the moles of NO required to produce 5.18 moles of N₂

The molar ratio of NO to N₂ is 6:5.

5.18molN_2 \times \frac{6molNO}{5molN_2} = 6.22molNO

Step 4: Calculate the mass corresponding to 6.22 moles of NO

The molar mass of NO is 30.01 g/mol.

6.22mol \times \frac{30.01g}{mol} =186 g

4 0
3 years ago
How many atoms are in 6.3 moles of calcium
KIM [24]
1 mol --------- 6.02x10²³ atoms
6.3 moles ---- ??

atoms = 6.3 * 6.02x10²³

= 3.7926x10²⁴ atoms

hope this helps!
6 0
3 years ago
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