Answer:
4009.21658986 Hz
Explanation:
v = Speed of sound in air = 348 m/s
L = Length of tube = 2.17 cm
Fundamental frequency for a tube where one end is closed and the other end open is given by
The fundamental frequency of the canal is 4009.21658986 Hz
ANOTHER RUNNING DOG
Explanation:
In the given question it is to find a suitable reference point to describe the motion of dog. Here I could suggest that it is better to compare the dog with another running dog to create the relative speed difference to get a reliable motion variation.
Because the motion of dog is in the linear with respect to the another dog and to the acceleration produced by the dog in the required interval is easy to calculate with respect to another dog which is already in motion.
Hence, I suggest that Motion of dog can be analysed better by analyse the motion variation of dog with another dog running.
Answer:
The net charges on inner surface is +3 C
The net charges on outer surface is +7 C
Explanation:
Given that,
Charge on spherical conducting shell = 10 C
Charge at center = -3 C
We know that,
The net electric field inside the conducting shell is zero. The Gaussian surface inside the conductor must have zero net charge.
We need to calculate the net charges on inner surface
The charge on the inner surface of the conductor must be equal and opposite to the present charge of the center.
So, The net charges on inner surface is +3 C.
We need to calculate the net charges on outer surface
Using formula of net charge
Put the value into the formula
Hence, The net charges on inner surface is +3 C
The net charges on outer surface is +7 C