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frutty [35]
3 years ago
12

John's car is stopped at a red light. When the light changes, the car accelerates to 45 miles per hour in 15 seconds. What is th

e approximate rate of change in the miles per hour that John's car accelerated? A) 3 miles per hour per second B) 12 miles per hour per second C) 15 miles per hour per second D) 30 miles per hour per second
Mathematics
2 answers:
Ede4ka [16]3 years ago
5 0
Initial velocity of John's car (V1) = 0 miles per hour
Final velocity of John's car (V2) = 45 miles per hour
Time taken for acceleration = 45 seconds
Then
Acceleration = (V2 - V1)/Time taken
                     = (45 - 0)/15 miles per hour per second
                     = 45/15 miles per hour per second
                     = 3 miles per hour per second.
So the approximate rate of change in the miles per hour that John's car accelerated is 3 miles per hour per second. The correct option among all the options given in the question is option "A".

irinina [24]3 years ago
3 0

The answer is 3 miles per hour.


You add 15+15+15 and you get 45

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The volume of cylinder is 1205.76 cubic inches

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We have to find the volume of cylinder

<em><u>The volume of cylinder is given by formula:</u></em>

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<em><u>Given dimensions are:</u></em>

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\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(3,\:5\right),\:\left(x_2,\:y_2\right)=\left(-2,\:10\right)\\\\m=\frac{10-5}{-2-3}\\\\m=\frac{5}{-5}\\\\simplify\\\\m=-1

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\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(5,\:-7\right),\:\\\left(x_2,\:y_2\right)=\left(-2,\:-7\right)\\\\m=\frac{-7-\left(-7\right)}{-2-5}\\\\m=\frac{-7+7}{-7} \\\\m = \frac{0}{7}\\\\Simplify\\\\m =0

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