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Fudgin [204]
3 years ago
14

Paula spots a glider located at an angle of elevation of 42 degrees. the distance between the glider and paula is 3280 feet. to

the nearest foot, what is the height of the glider h from the ground?
Physics
2 answers:
Anna71 [15]3 years ago
6 0

distance = 3280 feet. This is the triangle's hypotenuse.

The distance from the ground is the opposite side as it is opposite the angle 42˚


Sin = Opposite/Hypotenuse

Sin(42) = Opposite/3280   Answer: 2195 feet

Cross multiply

Opposite = sin(42) x 3280

Opposite = 2194.7 feet


fomenos3 years ago
3 0
This situation represents triangle with one angle of 90 degrees. That angle is directly below glider. That means that we can you basic trigonometry functions.

sin42 = h/3280

Now we express h.
h = 3280* sin42 
h = 2195 feet

The answer is 2195 feet.
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Answer:

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Explanation:

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Where:

r = position vector at time t.

x0 = initial horizontal position.

v0 = initial velocity.

t = time.

α = launching angle.

y0 = initial vertical position

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Please, see the attached figure for a graphical description of the problem.

When the ball is caught, its position vector will be (see r1 in the figure):

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Since the frame of reference is located at the point where the ball was hit, x0 and y0 = 0. Then:

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Let´s use the equation of the y-component of r1 to obtain the time of flight of the ball:

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0 = -0.873 m + 37.2 m/s · t · sin 49.3° - 4.9 m/s² · t²

Solving the quadratic equation:

t = 0.03 s and t = 5.72 s.

It would be impossible to catch the ball immediately after it is hit at t = 0.03 s. Besides, the problem says that the ball was caught on its way down. Then, the time of flight of the ball is 5.72 s.

With this time, we can calculate r1x which is the horizontal distance traveled by the ball from home:

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r1x = 1.39 × 10² m

The distance traveled by the fielder is (1.39 × 10² m - 1.09 × 10² m) 30.0 m.

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