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Fudgin [204]
4 years ago
14

Paula spots a glider located at an angle of elevation of 42 degrees. the distance between the glider and paula is 3280 feet. to

the nearest foot, what is the height of the glider h from the ground?
Physics
2 answers:
Anna71 [15]4 years ago
6 0

distance = 3280 feet. This is the triangle's hypotenuse.

The distance from the ground is the opposite side as it is opposite the angle 42˚


Sin = Opposite/Hypotenuse

Sin(42) = Opposite/3280   Answer: 2195 feet

Cross multiply

Opposite = sin(42) x 3280

Opposite = 2194.7 feet


fomenos4 years ago
3 0
This situation represents triangle with one angle of 90 degrees. That angle is directly below glider. That means that we can you basic trigonometry functions.

sin42 = h/3280

Now we express h.
h = 3280* sin42 
h = 2195 feet

The answer is 2195 feet.
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devlian [24]

Answer:

As the temperature increases, the kinetic energy of the particles increases.

Explanation:

When the temperature of the substance increases, the velocity increases which makes the movement of the particles to speed up. This causes the particles to increase. Therefore, as the temperature increases, the kinetic energy of the particles also increases.

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  • initial velocity=u=15m/s
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  • Time=t=5s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{75-15}{5}

\\ \sf\longmapsto Acceleration=\dfrac{60}{5}

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A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result
Virty [35]

Hello!

A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result? A) law of differential mass B) law of conservation of momentum C) law of unequal forces D) law of accelerated collision

We have the following data¹:

ΔP (momentum before impact) = ?  

mA (mass) = 10 kg

vA (velocity) = 5 m/s

mB (mass) = 5 kg

vB (velocity) = 0 m/s

Solving:

ΔP = mA*vA + mB*vB

ΔP = 10 kg*5 m/s + 5 kg*0 m/s

ΔP = 50 kg*m/s + 0 kg*m/s

Δp = 50 kg*m/s ← (momentum before impact)

We have the following data²:

ΔP (momentum after impact) = ?  

mA (mass) = 10 kg

vA (velocity) = 0 m/s

mB (mass) = 5 kg

vB (velocity) = 10 m/s

Solving:

Δp = mA*vA + mB*vB

Δp = 10 kg*0 m/s + 5 kg*10 m/s

Δp = 0 kg*m/s + 50 kg*m/s

Δp = 50 kg*m/s ← (momentum after impact)

*** Then, which principle explains the result ?

Law of conservation of momentum, <u>since the total momentum of body A and B before impact is equal to the total momentum of body A and B after impact.</u>

Note:  Bodies of different masses and velocities may have the same kinetic energy, if proportionality between the units is maintained it can occur that they have the same kinetic energy.

Answer:

B) law of conservation of momentum

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3 years ago
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Answer:

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