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Fudgin [204]
3 years ago
14

Paula spots a glider located at an angle of elevation of 42 degrees. the distance between the glider and paula is 3280 feet. to

the nearest foot, what is the height of the glider h from the ground?
Physics
2 answers:
Anna71 [15]3 years ago
6 0

distance = 3280 feet. This is the triangle's hypotenuse.

The distance from the ground is the opposite side as it is opposite the angle 42˚


Sin = Opposite/Hypotenuse

Sin(42) = Opposite/3280   Answer: 2195 feet

Cross multiply

Opposite = sin(42) x 3280

Opposite = 2194.7 feet


fomenos3 years ago
3 0
This situation represents triangle with one angle of 90 degrees. That angle is directly below glider. That means that we can you basic trigonometry functions.

sin42 = h/3280

Now we express h.
h = 3280* sin42 
h = 2195 feet

The answer is 2195 feet.
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Line segment gj is a diameter of circle l. angle k measures (4x 6)°. circle l is inscribed with triangle g j k. line segment g j
choli [55]

The value of x in the given right triangle in a semicircle is determined as 21.

<h3>What is the measure of a triangle in a semicircle?</h3>

The triangle in a semicircle is always a right angle triangle.

From the figure shown, we can say that the triangle  G J K is right triangle and m<K = 90degrees.

Given that m<K = 4x + 6, we will can use the following equation to find the value of x as shown:

4x + 6 = 90

4x = 90 - 6

4x = 84

x = 21

Thus, the value of x in the given right triangle in a semicircle is determined as 21.

Learn more about right angle here: brainly.com/question/64787

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8 0
2 years ago
Find the acceleration that can result from a net force of 13 N exerted on a 3.6-kg cart. (Note: The unit N/kg is equivalent to m
STatiana [176]

Answer:

a = 3.61[m/s^2]

Explanation:

To find this acceleration we must remember newton's second law which tells us that the total sum of forces is equal to the product of mass by acceleration.

In this case we have:

F = m*a\\\\m=mass = 3.6[kg]\\F = force = 13[N]\\13 = 3.6*a\\a = 3.61[m/s^2]

7 0
3 years ago
A sound source is moving at 80 m/s toward a stationary listener that is standing in still air (a) Find the wavelength of the sou
Setler [38]

Answer:

a. wavelength of the sound, \vartheta = 1.315\vartheta_{o}

b. observed frequecy, \lambda = 0.7604\lambda_{o}

Given:

speed of sound source, v_{s} = 80 m/s

speed of sound in air or vacuum, v_{a} = 343 m/s

speed of sound observed, v_{o} = 0 m/s

Solution:

From the relation:

v = \vartheta \lambda        (1)

where

v = velocity of sound

\vartheta = observed frequency of sound

\lambda = wavelength

(a) The wavelength of the sound between source and the listener is given by:

\lambda = \frac{v_{a}}{\vartheta }         (2)

(b) The observed frequency is given by:

\vartheta = \frac{v_{a}}{v_{a} - v_{s}}\vartheta_{o}

\vartheta = \frac{334}{334 - 80}\vartheta_{o}

\vartheta = 1.315\vartheta_{o}                (3)

Using eqn (2) and (3):

\lambda = \frac{334}{1.315} = \frac{1}{1.315}\frac{v_{a}}{\vartheta_{o}}

\lambda = 0.7604\lambda_{o}

4 0
3 years ago
A student rides her bike to school. Her school is 5 miles from home. She travels at an average rate of 15 miles per hour. How mu
Elden [556K]

Answer:

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Explanation:

3 0
2 years ago
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tangare [24]
The best and most correct answer to the question is :
Alpha particles
Beta particles
Gamma rays
Cosmic radiation
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8 0
3 years ago
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