Answer:
Measurement is the assignment of a number to a characteristic of an object or event
Explanation:
Answer:
The Moon blocks the suns light from hitting the surface of the earth
Answer:
c)the gravitational forces of people is so small it is overshadowed by that of earth.
Explanation:
The gravitational force between two objects is given by:
![F=G\frac{m_1 m_2}{r^2}](https://tex.z-dn.net/?f=F%3DG%5Cfrac%7Bm_1%20m_2%7D%7Br%5E2%7D)
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the distance between the two objects
From the formula, we see that the gravitational force depends on the masses of the objects: since the mass of the Earth (
is much much larger than the average mass of one person (80-100 kg), then the gravitational force exerted by the Earth on a person is also much much larger than the gravitational force between two people.
Answer:Most genes contain the information needed to make functional molecules called proteins. (A few genes produce regulatory molecules that help the cell assemble proteins.) The journey from gene to protein is complex and tightly controlled within each cell. It consists of two major steps: transcription and translation.
Explanation:
Answer:
Please see below as the answer is self-explanatory.
Explanation:
- We can take the initial velocity vector, which magnitude is a given (67 m/s) and project it along two directions perpendicular each other, which we choose horizontal (coincident with x-axis, positive to the right), and vertical (coincident with y-axis, positive upward).
- Both movements are independent each other, due to they are perpendicular.
- In the horizontal direction, assuming no other forces acting, once launched, the supply must keep the speed constant.
- Applying the definition of cosine of an angle, we can find the horizontal component of the initial velocity vector, as follows:
![v_{avgx} = v_{o}*cos 50 = 67 m/s * cos 50 = 43.1 m/s (1)](https://tex.z-dn.net/?f=v_%7Bavgx%7D%20%3D%20v_%7Bo%7D%2Acos%2050%20%3D%2067%20m%2Fs%20%2A%20cos%2050%20%3D%2043.1%20m%2Fs%20%281%29)
- Applying the definition of average velocity, since we know the horizontal distance to the target, we can find the time needed to travel this distance, as follows:
![t = \frac{\Delta x}{v_{avgx} } = \frac{400m}{43.1m/s} = 9.3 s (2)](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5CDelta%20x%7D%7Bv_%7Bavgx%7D%20%7D%20%3D%20%5Cfrac%7B400m%7D%7B43.1m%2Fs%7D%20%3D%209.3%20s%20%20%282%29)
- In the vertical direction, once launched, the only influence on the supply is due to gravity, that accelerates it with a downward acceleration that we call g, which magnitude is 9.8 m/s2.
- Since g is constant (close to the Earth's surface), we can use the following kinematic equation in order to find the vertical displacement at the same time t that we found above, as follows:
![\Delta y = v_{oy} * t - \frac{1}{2} *g*t^{2} (3)](https://tex.z-dn.net/?f=%5CDelta%20y%20%3D%20v_%7Boy%7D%20%20%2A%20t%20-%20%5Cfrac%7B1%7D%7B2%7D%20%2Ag%2At%5E%7B2%7D%20%283%29)
- In this case, v₀y, is just the vertical component of the initial velocity, that we can find applying the definition of the sine of an angle, as follows:
![v_{oy} = v_{o}*sin 50 = 67 m/s * sin 50 = 51.3 m/s (4)](https://tex.z-dn.net/?f=v_%7Boy%7D%20%3D%20v_%7Bo%7D%2Asin%2050%20%3D%2067%20m%2Fs%20%2A%20sin%2050%20%3D%2051.3%20m%2Fs%20%284%29)
- Replacing in (3) the values of t, g, and v₀y, we can find the vertical displacement at the time t, as follows:
![\Delta y = (53.1m/s * 9.3s) - \frac{1}{2} *9.8m/s2*(9.3s)^{2} = 53.5 m (5)](https://tex.z-dn.net/?f=%5CDelta%20y%20%3D%20%2853.1m%2Fs%20%2A%209.3s%29%20-%20%5Cfrac%7B1%7D%7B2%7D%20%2A9.8m%2Fs2%2A%289.3s%29%5E%7B2%7D%20%3D%2053.5%20m%20%285%29)
- Since when the payload have traveled itself 400 m, it will be at a height of 53.5 m (higher than the target) we can conclude that the payload will be delivered safely to the drop site.