1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arte-miy333 [17]
3 years ago
14

Consider the following practical aspects of titration.

Chemistry
1 answer:
Rashid [163]3 years ago
7 0

Answer:

A) when the titration is nearing the end point in titration the color of the solution starts to change and the change in color does not disappear as fast as it was during the beginning of the titration  

B) The volume of NaOH required to permanently change the indicator at the end point is  a  drop of NaOH

c) The volume required by samples #2 and #3 will be the same i.e 19.90 mL of NaOH, if the concentration of KHP base used for the samples are the same

D) The volume required by samples #2 and #3 will be the same i.e 29.05 mL OF NaOH, if the concentration of Vinegar and base for the samples are the same

Explanation:

A) when the titration is nearing the end point in titration the color of the solution starts to change and the change in color does not disappear as fast as it was during the beginning of the titration  

B) The volume of NaOH required to permanently change the indicator at the end point is  a  drop of NaOH

c) The volume required by samples #2 and #3 will be the same i.e 19.90 mL of NaOH, if the concentration of KHP base used for the samples are the same

D) The volume required by samples #2 and #3 will be the same i.e 29.05 mL OF NaOH, if the concentration of Vinegar and base for the samples are the same

You might be interested in
What mass of Iron (III) acetate will be produced when 1.50 grams of iron reacts in acetic acid?
densk [106]

Answer:

Fe + H(C2H3O2) ........

4 0
2 years ago
HELP ASAP
Virty [35]
 <span>To find the molar mass, look at a periodic table for each element. 
Ibuprofen, C13 H18 and O2. Carbon has a molar mass of 12.01 g, Hydrogen has 1.008 g per mole, and Oxygen is 16.00 g per mole. 

C: 13 * 12.01 
H: 18 * 1.008 
O: 2 * 16.00 
Calculate that, add them all together, and that is the molar mass of C13H18O2. 
Molar mass: 206.274 

Next, you have 200mg in each tablet, with a ratio of C13H18O2 (molar mass) in GRAMS per Mole 
So, you need to convert miligrams into grams, which is 200 divided by 1000. 
0.2 g / Unknown mole = 206.274 g / 1 Mole 

This is a cross multiplying ratio where you're going to solve for the unknown moles of grams per tablet compared to the moles per ibuprofen. 
So, it's set up as: 
0.2 g * 1 mole = 206.274 * x 
0.2 = 206.274x 
divide each side by 206.274 to get X alone 
X = 0.00097 
or 9.7 * 10^-4 moles 

The last problem should be easy to figure out now that you have the numbers. 1 dose is 2 tablets, which is the moles we just calculated above, times four for the dosage. 
</span>
5 0
3 years ago
Read 2 more answers
The Arrhenius plot of the reaction has a downward slope of 1.5 x104. Calculate the time required to reduce the concentration of
madam [21]
1.5?10000 10% then add it up
4 0
2 years ago
If Steve self-pollinates, what is the likelihood that his offspring will be green?
Pani-rosa [81]

Answer:

100%

Explanation:

My teacher just asked this question.

6 0
3 years ago
It takes 495.0 kJ of energy to remove 1 mole of electron from an atom on the surface of sodium metal. How much energy does it ta
Zigmanuir [339]

Answer:

\lambda=241.9\ nm

Explanation:

The work function of the sodium= 495.0 kJ/mol

It means that  

1 mole of electrons can be removed by applying of 495.0 kJ of energy.

Also,  

1 mole = 6.023\times 10^{23}\ electrons

So,  

6.023\times 10^{23} electrons can be removed by applying of 495.0 kJ of energy.

1 electron can be removed by applying of \frac {495.0}{6.023\times 10^{23}}\ kJ of energy.

Energy required = 82.18\times 10^{-23}\ kJ

Also,  

1 kJ = 1000 J

So,  

Energy required = 82.18\times 10^{-20}\ J

Also, E=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

So,  

79.78\times 10^{-20}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{82.18\times 10^{-20}}

\lambda=\frac{10^{-26}\times \:19.878}{10^{-20}\times \:82.18}

\lambda=\frac{19.878}{10^6\times \:82.18}

\lambda=2.4188\times 10^{-7}\ m

Also,  

1 m = 10⁻⁹ nm

So,  

\lambda=241.9\ nm

6 0
3 years ago
Other questions:
  • Which of the following substances would you predict to have the highest ΔHvap?
    11·1 answer
  • A first-order reaction has a half-life of 29.2 s . how long does it take for the concentration of the reactant in the reaction t
    7·1 answer
  • “It is important we work together on this project; we want our group to succeed.” This statement reflects __________.
    14·1 answer
  • List three particals that make up atoms
    9·1 answer
  • Which process does not involve matter in the liquid state?
    8·1 answer
  • Why does my dogs poop look green?
    15·1 answer
  • The carbon tetrachloride molecule CCI 4 is
    12·1 answer
  • I AM GIVING AWAY 80 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    15·2 answers
  • Which best describes an element?
    14·2 answers
  • 3. In the apparatus below, the seawater is an example of a(n) ——
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!