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Blababa [14]
3 years ago
9

All of the following equations are statements of the ideal gas law except

Chemistry
1 answer:
evablogger [386]3 years ago
3 0

Answer:

  • The first equation, <em>a. PV = nRT</em>, <u>is not</u> <em>a valid statement of the ideal gas law.</em>

Explanation:

The basic expression for the<em> ideal gas law</em> is:

  • pV=nRT      .......... [Equation 1]

Where:

  • n is the number of moles of the gas
  • V is the volume occupied by the gas
  • p is the pressure exerted by the gas molecules
  • T is the temperature in absolute scale (Kelvin)
  • R is the Universal gas constant (0.0821 atm-liter /K-mol or the equivalents in other units)

You can perform different algebraic operations to obtain equivalent equations:

<u>Choice b) Divide equation 1 by T and you get</u>:

  • pV / T = nR, which is the choice b. from your list.

<u>Choice c) Divide equation 1 by n × V and you get</u>:

  • p/n = RT / V, which is the choice c. from your list.

<u>Choice d) Divide equation 1  n × T and you get</u>:

  • pV / (nT) = R, which is the choice d. from your list.

The choice a. p = nRTV states that p and V are in direct relation, when the ideal gas law states that p and V are inversely related, so that equation is wrong.

<u>Conclusion: </u>the choice a, p = nRTV, is not a statement of the ideal gas law.

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The third option does not obey the law of conservation of mass.

Option 3.

Explanation:

The law of conservation of mass states that the sum of the masses of reactants should be equal to the sum of the masses of the products.

For example, if we consider the first option to verify if it obeys law of conservation of mass or not, 2 Na + Cl₂ → 2 NaCl

So one way to verify it is to find the mass of Na, then multiply it with 2, and then add this with 2 times of mass of chlorine. So this sum should be equal to the 2 times mass of NaCl. But it is somewhat lengthy.

Another way to easily determine this is to check if the elements are present equally in both sides. Such as, in reactant side and product side 2 atoms of Na is present . Similarly, the Cl atoms are also present in equal number in both reactant and product side. Thus this obeyed the law of conservation of mass.

Like this, if we see the second option, there also 1 atom of Na is present in reactant and product side and 2 molecules of H is present in reactant and product side, 1 oxygen is present in reactant and product side and 1 Cl is present in reactant and product side. So it also obeys the law of conservation of mass.

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