Question

Which element has the electron configuration [Xe] 6s2 4f14 5d10 6p2?

Answer 1

That is Pb (Lead) All you need to do is look at he last orbital and find that on the periodic table!

Answer 2

Answer: Lead (Pb)

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

The given element is a p block element as the last electron enters the p orbital. The nearest noble gas is Xenon with 54 electrons.

The electrons are filled according to Afbau's rule in order of increasing energies and the electronic configuration in terms of noble gs configuration is:  

$[Xe]6s^24f^{14}5d^{10}6p^2$

Total number of electrons = 54+2+14+10+2= 82

The element which has 82 electrons and thus the atomic number is 82, the element is lead with symbol $Pb$