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4 years ago

The following compounds have similar molecular weights. which would be expected to have the lowest boiling point?

Chemistry

1 answer:

Oksanka [162]4 years ago

3 0

Answer:

Methane (B) is expected to have the lowest boiling point.

Explanation:

There are to ways of solving this problem.

The first one is considering the physical state of matter that this compounds are found in normal conditions (room temperature):

(A) calcium carbonate - solid

(B) methane - gas

(D) dimethyl ether (CH₃OCH₃) - liquid

Methane is the only gas, therefore it has the lowest boiling point.

The second one is considering the molecular interactions between the molecules of each compound:

(A) calcium carbonate - it is a salt - eletrostatic interactions between ions - very strong

(B) methane - non-polar molecule - induced dipole - very weak

(D) dimethyl ether (CH₃OCH₃) - liquid - dipole-dipole - relatively strong

The intermolecular interactions in methane are the weakest, therefore it has the lowest boiling point.

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The words that complete the blanks are hypothesis and experimentation.

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2 years ago

Switching one substance for another is called..?

Dmitry_Shevchenko [17]

Answer:

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3 years ago

Read 2 more answers

What is an extensive property that can be calculated?

padilas [110]

Answer: The property which depends on the quantity of the substance is called an extensive property. The free energy change for a reaction (Δ G) depends on the quantity of the substance and is therefore an extensive property. It shows the additive nature. The extensive property Δ G is easily calculated from the formula, ΔG = -nFE cell.

Explanation:

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3 years ago

Question 2 (1 point)

alisha [4.7K]

To calculate an electron configuration, divide the periodic table into sections to represent the atomic orbitals, the regions where electrons are contained. Groups one and two are the s-block, three through 12 represent the d-block, 13 to 18 are the p-block and the two rows at the bottom are the f-block.

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3 years ago

To begin the experiment, 1.11g of methane CH4 is burned in a bomb calorimeter containing 1000 grams of water. The initial temper

yaroslaw [1]

In order to calculate the enthalpy of the reaction, we first calculate the heat released using the given formula.
Q = mc<span>ΔT
Q = 1000 x 4.184 x (35.65 - 24.85)
Q = 45187.2 J = 45.2 kJ

Now, we determine the moles of methane that were burned.
Moles = mass / Mr
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The enthalpy of a reaction is the energy released per mole, so the enthalpy in this case is:
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3 years ago