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dmitriy555 [2]
4 years ago
9

The following compounds have similar molecular weights. which would be expected to have the lowest boiling point?

Chemistry
1 answer:
Oksanka [162]4 years ago
3 0

Answer:

Methane (B) is expected to have the lowest boiling point.

Explanation:

There are to ways of solving this problem.

The first one is considering the physical state of matter that this compounds are found in normal conditions (room temperature):

(A) calcium carbonate  - solid

(B) methane  - gas

(C) methanol (CH₄O)  - liquid

(D) dimethyl ether (CH₃OCH₃) - liquid

Methane is the only gas, therefore it has the lowest boiling point.

The second one is considering the molecular interactions between the molecules of each compound:

(A) calcium carbonate  - it is a salt - eletrostatic interactions between ions - very strong

(B) methane  - non-polar molecule - induced dipole - very weak

(C) methanol (CH₄O)  - polar molecule - dipole-dipole - relatively strong

(D) dimethyl ether (CH₃OCH₃) - liquid - dipole-dipole - relatively strong

The intermolecular interactions in methane are the weakest, therefore it has the lowest boiling point.

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Answer: The volume in the balloon at the higher altitude is 260 L

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

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V_1 = initial volume of gas = 233 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^0C=(22.0+273)K=295K

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Now put all the given values in the above equation, we get:

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The volume in the balloon at the higher altitude is 260 L

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