The following compounds have similar molecular weights. which would be expected to have the lowest boiling point?

Chemistry

1 answer:

Oksanka [162]4 years ago

3 0

Answer:

Methane (B) is expected to have the lowest boiling point.

Explanation:

There are to ways of solving this problem.

The first one is considering the physical state of matter that this compounds are found in normal conditions (room temperature):

(A) calcium carbonate - solid

(B) methane - gas

(D) dimethyl ether (CH₃OCH₃) - liquid

Methane is the only gas, therefore it has the lowest boiling point.

The second one is considering the molecular interactions between the molecules of each compound:

(A) calcium carbonate - it is a salt - eletrostatic interactions between ions - very strong

(B) methane - non-polar molecule - induced dipole - very weak

(D) dimethyl ether (CH₃OCH₃) - liquid - dipole-dipole - relatively strong

The intermolecular interactions in methane are the weakest, therefore it has the lowest boiling point.

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The molecular formula of butane is C4H10. It is obtained from petroleum and is used commonly in LPG (Liquefied Petroleum Gas) cy

guajiro [1.7K]

Answer:

See attached picture.

Explanation:

Hello.

In this case, since butane has two common occurring structures, n-butane and isobutane, there is a way in which the tert-butyl radical can be formed upon the removal of a hydrogen from the isobutane form of butane as shown on the attached picture, wherein you can see that the radical is named by "tert" since the central carbon is bonded to three carbon atoms, that is why we classify it as tertiary. Moreover, it is a radical due to the presence of the bolded dot next to the tertiary carbon suggesting that it is very likely to bond with an other atom.

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