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dmitriy555 [2]
4 years ago
9

The following compounds have similar molecular weights. which would be expected to have the lowest boiling point?

Chemistry
1 answer:
Oksanka [162]4 years ago
3 0

Answer:

Methane (B) is expected to have the lowest boiling point.

Explanation:

There are to ways of solving this problem.

The first one is considering the physical state of matter that this compounds are found in normal conditions (room temperature):

(A) calcium carbonate  - solid

(B) methane  - gas

(C) methanol (CH₄O)  - liquid

(D) dimethyl ether (CH₃OCH₃) - liquid

Methane is the only gas, therefore it has the lowest boiling point.

The second one is considering the molecular interactions between the molecules of each compound:

(A) calcium carbonate  - it is a salt - eletrostatic interactions between ions - very strong

(B) methane  - non-polar molecule - induced dipole - very weak

(C) methanol (CH₄O)  - polar molecule - dipole-dipole - relatively strong

(D) dimethyl ether (CH₃OCH₃) - liquid - dipole-dipole - relatively strong

The intermolecular interactions in methane are the weakest, therefore it has the lowest boiling point.

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Answer:

\text{ }1.25\times10^{23}\text{ formula units}

Explanation:

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We start by getting the number of moles

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Thus, we have the number of moles as follows:

\frac{41.5}{200}\text{ = 0.2075 mol}

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1\text{ mole = 6.02 }\times10^{22}\text{ formula units}

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0.2075\text{ }\times6.02\times10^{23}\text{ = }1.25\times10^{23}\text{ formula units}

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