From the information given, cannon ball weighs 40 kg and has a potential energy of 14000 J.
We need to find its height.
We will use the formula P.E = mgh
Therefore h = P.E / mg
where P.E is the potential energy,
m is mass in kg,
g is acceleration due to gravity (9.8 m/s²)
h is the height of the object's displacement in meters.
h = P.E. / mg
h = 14000 / 40 × 9.8
h = 14000 / 392
h = 35.7
Therefore the canon ball was 35.7 meters high.
1,) C
2,) C
Hope this helps
Answer:
reaching a speed of 30 meters per second in 6 seconds.
During the 6 seconds, the car has traveled
a distance of
1. 180 m
2. 60 m
3. 15 m
4. 30 m
5. 90 m
Explanation:
Answer:
0.3405V
Explanation:
#Given a magnetic field of 
, diameter= 18.5cm(r=9.25cm or 0.0925m), we find the magnetic flux of the loop as:
we can now calculate the induced emf, 
:
Hence, the induced emf of the loop is 0.3405V
