Answer:
50N
The table is managing to keep the dog up, the dog is not moving up or down so the force that the table applies to the dog must be equal to the dogs weight - I draw this conclusion from Newton's 3rd law.
W= mg
W = 5 × 9.8
W = 49N
round to.one significant figure = 50N
The acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.
The given parameters;
- mass of the car, m = 1400 kg
- Initial velocity of the car, u = 25 m/s
- coefficient of kinetic friction, μ = 0.7
The acceleration of the car is calculated as follows;
a = μg
a = 0.7 x 9.8
a = 6.86 m/s²
The time taken for the car to stop is calculated by using Newton's second law of motion;
F = ma

Thus, the acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.
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