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vodka [1.7K]
3 years ago
11

If the mass of one object is tripled, and the distance between them is doubled, how does the force of gravity change?

Physics
1 answer:
fredd [130]3 years ago
8 0
Force between two object is given by F = Gm1m2/r^2
<span>If the mass of one object is tripled, and the distance between them is doubled,</span>
then F(new) = Gm13m2/(2r)^2 = 3Gm1m2/4r^2 = 3/4 x Gm1m2/r^2 = 3/4 x F
i.e. F(new) = 3/4 multiplied by F.
Therefore, Force is multiplied by 3/4.
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The gravitational force between the charged constituents of the atom is negligible compared with the electric force between them
katrin2010 [14]

Answer: The initial force is reduced a factor 1/4 when the separation between charge is doubled

Explanation: As it well known the electric force between two charges is given by:

Finitial=k*q1*q2/d^2 where d is the distance between charges and k is a constant

if the distance is doubled this means 2*dinitial thus the new force is equal to F initial* 1/4

6 0
3 years ago
The sun produces large amounts of energy. By what process does the sun produce energy?
AlladinOne [14]
The sun produces energy by converting gravitational potential energy into radiation via quantum processes in the nucleus of the atoms.

Since the mass of the sun and it's temperature are not quite enough to generate nuclear FUSION on their own, quantum tunneling is the primary process by which nuclear fusion occurs in our sun, SOL. FISSION also occurs as a result of this fusion.

Additionally, gravitational potential energy is also the reason that supernovae are so bright. Cool!
8 0
3 years ago
Choose the scenario in which the sound frequency of the waves is higher.
mrs_skeptik [129]

Answer:

B) the sound source moves towards you at 100 m/sec

Explanation:

The Dopper Effect is a phenomenon that occur when there is relative motion between an observer and a source of a wave. When this situation occurs, there is an apparent shift in frequency of the wave, as observed by the observer.

The apparent frequency observed by the observer is given by

f'=\frac{v\pm v_o}{v\pm v_s}f

where

f is the original frequency of the wave

f' is the apparent frequency

v is the speed of the wave

v_o is the velocity of the observer (positive if moving towards the source of the wave, negative otherwise)

v_s is the velocity of the source (negative if moving towards from the observer, positive otherwise)

In this problem, we want to find the scenario in which the sound frequency is higher.

We see that in all 4 scenarios, the sound source is moving: this means we have to find the scenario in which the denominator of the equation is smaller.

First of all, we notice the sound source moves towards the observer, v_s is negative, so the denominator is higher: this means that the correct option must be either A or B.

Also, we notice that since v_s is negative, a value larger in magnitude will mean a smaller denominator: therefore, the correct answer will be

B) the sound source moves towards you at 100 m/sec

Since this situation will make the denominator of the formula the smallest possible.

5 0
3 years ago
A man, holding a weight in each hand, stands at the center of a horizontal frictionless rotating turntable. The effect of the we
Alex_Xolod [135]

Answer:

 w = 2w₀     the angular velocity of man doubles

Explanation:

In this exercise, releasing the weights reduces the moment of inertia

       I= I₀ / 2

Therefore, since the platform system plus man is isolated, the kinetic moment must be conserved

         L₀ = L

       I₀ w₀ = I w

       I₀ w₀ = I₀ / 2 w

       w = 2w₀

therefore the angular velocity of man doubles

7 0
3 years ago
A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes
Nitella [24]

Answer:

The value of F= - 830 N

Since the force is negative, it implies direction of the force applied was due south.

Explanation:

Given data:

Mass = 1000-kg

Distance, d = 240 m

Initial velocity, v1 = 20.0 m/s

Final velocity, v2 = 0 (since the car came to rest after brake was applied)

v2²= v1² + 2ad (using one of the equation of motion)

0=  20² + (2 x a x  240)

0= 400 + 480 a

a = - 400/480

a = - 0.83 m/s²

Then, imputing the value of a into

F = ma

F = 1000 kg x ( - 0.83 m/s²)

F= - 830 N

The car was driving toward the north, and since the force is negative, it implies direction of the force applied was due south.

3 0
3 years ago
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