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tresset_1 [31]
3 years ago
15

First, let us consider an object launched vertically upward with an initial speed v. Neglect air resistance. Part B) At the top

point of the flight, what can be said about the projectile's kinetic and potential energy?
A). Both kinetic and potential energy are at their maximum values.
B).Both kinetic and potential energy are at their minimum values.
C).Kinetic energy is at a maximum; potential energy is at a minimum.
D).Kinetic energy is at a minimum; potential energy is at a maximum.
Physics
1 answer:
harina [27]3 years ago
3 0

Answer:

Option d is the correct option Kinetic energy is minimum while as potential energy is maximum

Explanation:

At the top most point of the flight since it cannot reach any further up in the vertical direction thus the potential energy at this position shall be maximum. Now since the total energy of the projectile is conserved so the remaining kinetic energy shall be minimum at that point so as the sum of the kinetic and potential energies remain constant.

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what happens to a circuits resistance, voltage, and current when you increase the diameter of the wire in the circuit?
zhannawk [14.2K]

Answer:

Option D.

Resistance (R) decreases

Voltage (V) is constant

Current (I) increases

Explanation:

We'll begin by writing an equation relating resistance and diameter of a wire. This is given below:

R = ρL/A ......... (1)

A = πr² (since the wire is circular in shape)

r = d/2

A = πr² = π(d/2)²

A = πd²/4

Substitute the value of A into equation 1

R = ρL/A

R = ρL ÷ A

R = ρL ÷ πd²/4

R = ρL × 4/πd²

R = 4ρL /πd²

Where:

R is the resistance of the wire.

ρ is the resistivity of the wire.

L is the length of the wire.

A is the cross sectional area of the wire.

r is the radius.

d is the diameter of the wire

From equation (1) above, we can say that the resistance (R) is inversely proportional to the square of the diameter of the wire. This implies that an increase in the diameter of the wire will result in a decrease of the resistance. Also, a decrease in the diameter of the wire will result in an increase in the resistance of the wire.

1. Since the diameter of the wire is increase, therefore, the resistance of the wire will decrease.

2. From ohm's law,

V = IR

Divide both side by I

R = V/I

Where:

R is the resistance

V is the voltage

I is the current

From the above equation, the resistance (R) is directly proportional to the voltage (V) and inversely proportional to the current (I).

If we keep the voltage constant, this means that an increase in the resistance will lead to a decrease in the current. Also, a decrease in the resistance will lead to an increase in the current.

Since the resistance of the wire decrease, the current will increase.

From the illustrations made above, an increase in the diameter of the wire will lead to:

1. Decrease in resistance.

2. Voltage is constant.

3. Increase in current.

5 0
4 years ago
Please answerASAP
Illusion [34]

Answer:

8.9 m/s^2

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the lenght of the pendulum

g is the acceleration due to gravity at the location of the pendulum

We notice from the formula that the period of a pendulum does not depend on the mass of the system

In this problem:

-The pendulum comes back to the point of release exactly 2.4 seconds after the release. --> this means that the period of the pendulum is

T = 2.4 s

- The length of the pendulum is

L = 1.3 m

Re-arranging the equation for g, we can find the acceleration due to gravity on the planet:

g=(\frac{2\pi}{T})^2 L=(\frac{2\pi}{2.4})^2(1.3)=8.9 m/s^2

7 0
4 years ago
A heat pump with a COP of 3.0 is used to heat air contained in a 1205.4 m3 of well-insulated, rigid tank. Initially the pressure
kati45 [8]

Answer:

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Explanation:

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4 0
3 years ago
What is the efficiency of a ramp if the input work is 96 J and the output work is 24 J?
iren2701 [21]

Answer:It is 200

Explanation: GOOGLE

7 0
3 years ago
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yuradex [85]
The picture won’t load
5 0
3 years ago
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