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3 years ago

Which best describes what is made of matter?

Physics

2 answers:

EastWind [94]3 years ago

8 0

Anything that has mass and occupies volume is made of matter.

a_sh-v [17]3 years ago

3 0

Matter is made up of molecules and atoms

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what voltage would produce a current of 100A through an aluminum wire that has a resistance of 3.44x10^-4 ohm?

Serga [27]

Voltage = Current x Resistance
Voltage(?) = 100 x 1.98x10^-4 ohms 

Voltage = Current x Resistance 
Voltage(?) = 250 x 2.09x10^-4 ohms 

Voltage = Current x Resistance 
Voltage(?) = 100 x 3.44x10^-4 ohms

7 0

2 years ago

Two objects were lifted by a machine. One object had a mass of 5000 kg, and was lifted at a speed of 2 m/sec. The other had a ma

Leokris [45]

Equation for ke = 1/2mv^2
1) ke = 1/2 x 5000 x (2x2)
= 10,000J
2) ke = 1/2 x 4000 x (3x3)
= 18,000J
So Object 2 has more Kinetic Energy

3 0

3 years ago

How is acceleration related to force when mass is constant, according to Newton's second law of motion?

kherson [118]

Answer:

According to Newton's second law of motion, acceleration is directly proportional to force. As the force increases (when mass is constant), the acceleration increases. This can be shown in the following formula.

$f = ma$

$a = \frac{f}{m}$

f = force

m = mass

a = acceleration

5 0

3 years ago

Read 2 more answers

A photon with a frequency of 5.48 × 1014 hertz is emitted when an electron in a mercury atom falls to a lower energy level. Iden

ludmilkaskok [199]

The color should be green.

3 0

3 years ago

A cold beverage can be kept cold even a warm day if it is slipped into a porous ceramic container that has been soaked in water.

Arisa [49]

Answer:

The rate at which the container is losing water is 0.0006418 g/s.

Explanation:

Under the assumption that the can is a closed system, the conservation law applied to the system would be: $E_{in}-E_{out}=E_{change}$ , where $E_{in}$ is all energy entering the system, $E_{out}$ is the total energy leaving the system and, $E_{change}$ is the change of energy of the system.
As the purpose is to kept the beverage can at constant temperature, the change of energy ( $E_{change}$ ) would be 0.
The energy that goes into the system, is the heat transfer by radiation from the environment to the top and side surfaces of the can. This kind of transfer is described by: $Q=\varepsilon*\sigma*A_S*(T_{\infty}^4-T_S^4)$ where $\varepsilon$ is the emissivity of the surface, $\sigma=5.67*10^{-8}\frac{W}{m^2K}$ known as the Stefan–Boltzmann constant, $A_S$ is the total area of the exposed surface, $T_S$ is the temperature of the surface in Kelvin, $T_{\infty}$ is the environment temperature in Kelvin.
For the can the surface area would be ta sum of the top and the sides. The area of the top would be $A_{top}=\pi* r^2=\pi(0.0252m)^2=0.001995m^2$ , the area of the sides would be $A_{sides}=2*\pi*r*L=2*\pi*(0.0252m)*(0.09m)=0.01425m^2$ . Then the total area would be $A_{total}=A_{top}+A_{sides}=0.01624m^2$
Then the radiation heat transferred to the can would be $Q=\varepsilon*\sigma*A_S*(T_{\infty}^4-T_S^4)=1*5.67*10^{-8}\frac{W}{m^2K}*0.01624m^2*((32+273K)^4-(17+273K)^4)=1.456W$ .
The can would lost heat evaporating water, in this case would be $Q_{out}=\frac{dm}{dt}*h_{fg}$ , where $\frac{dm}{dt}$ is the rate of mass of water evaporated and, $h_{fg}$ is the heat of vaporization of the water ( $2257\frac{J}{g}$ ).
Then in the conservation balance: $Q_{in}-Q_{out}=Q_{change}$ , it would be $1.45W-\frac{dm}{dt}*2257\frac{j}{g}=0$ .
Recall that $1W=1\frac{J}{s}$ , then solving for $\frac{dm}{dt}$ : $\frac{dm}{dt}=\frac{1.45\frac{J}{s} }{2257\frac{J}{g} }=0.0006452\frac{g}{s}$

5 0

2 years ago