Answer:
2666.7 hours
Explanation:
The key to solve this problem is that we are given the propane gas consumed in one hour by giving us the information of the volume consumed at 1 atm, 298 K (25 +273). Using the gas law we can calculate the rate of consumption of propane per hour, and from here we can calculate its mass and converting it to gallons and finally diving the 400 gallos by this number.
PV = nRT ∴ n = PV/RT
n = 1 atm x 165 L/ (0.08206 Latm/kmol x 298 K ) = 6.75 mol propane
Mass propane :
6.75 mol x 44 g/mol = 296.88 g
convert this to Kg:
296.88 g/ 1000 g/Kg = 0.30 Kg
calculate the volume in liters this represents by dividing by the density:
0.30 Kg / 0.5077 Kg/L = 0.59 L
changing this to gallons
0.59 L x 1 gallon/3.785 L = 0.15 gallon
and finally calculate how many hours the 400 gallons propane tank will deliver
400 gallon/ 0.15 gallon/hr = 2666.7 hr
An instrument with high amplitude has loud sound. An instrument with low amplitude has soft sound.
Answer:
The answers are as given in the attachment
Explanation:
The application of the de brogile equation was used and appropriate substitution were made as shown in the attachment
Answer:
Chemical equation for photosynthesis
A water + carbon dioxide + sunlight → oxygen + glucose. B carbon + oxygen → carbon dioxide. C hydrogen + oxygen → water.
Explanation: This same photosynthesis cycle is usually expressed as: 6CO2 + 6H2O + 6O2 + C6H12O6. This implies that the solute, six carbon dioxide molecules plus 6 hydroxyl groups, are translated into something like a sugar molecule or six oxygen molecules, the goods, exploiting light energy absorbed the chlorophyll (implied by arrow).
Answer:
1: 38
2: 39
3: 40
4: 41
Explanation:
The mass in amu is the weight of the neutrons and protons in the element. The mass number is the number neutrons and protons you have in an element. Both neutrons and protons have a weight of 1 amu. Since you can't have a decimal of a subatomic particle, you have to round to the nearest whole number.
