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3 years ago

How much kinetic energy does a 7.2-kg dog need to make a vertical jump of 1.2 m? the acceleration due to gravity is 9.8m / s^2

2 answers:

7 0

$E_k=mgh\\\\m=7.2\ kg\\\\g=9.8\ m/s^2\\\\h=1.2\ m\\\\E_k=7.2\cdot9.8\cdot1.2=84.672\ \left[\frac{kgm^2}{s^2}\right]=84.672\ [J]$

34kurt3 years ago

3 0

Assuming that no energy is wasted,
Use the equation Gpe=mgh
Mass*gravity*height
1.2*7.2*9.8=
84.672
(The answer might be wrong I did it in my head)

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1. What is the kinetic energy of a 1.75 kg ball travelling at a speed of 54 m/s?

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We conclude that the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.

Explanation:

Given

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Velocity v = 54 m/s

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3 years ago

A 5.00-m-long uniform ladder, weighing 200 N, rests against a smooth vertical wall with its base on a horizontal rough floor, a

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Answer:

0.488 m

Explanation:

If θ be the angle ladder makes with the plane

cos θ = 1.2 / 5

Tan θ = 4.04

Let the height a person of weight 600 N can climb be h from the ground .

Distance from the base point where ladder touches the floor = h / tanθ

= h / 4.04

Total reaction force = total downward force

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800 N

Frictional force = μ R

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= 160 N

Taking moment of force about the point on the ladder where it touches the floor and balancing them

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R₁ =μ R )

= 200 x 1.2 x .5 + 600 x h / tanθ = 160 x 1.2 / tanθ

120 - 600 h / 4.04 = 47.52

120 - 47.52 = 600 h / 4.04

72.48= 148.51 h

h = 0.488 m

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