Answer:
The driver's average velocity is 82.35 km/h.
Explanation:
Given:
The motion of the driver can be divided into 3 parts:
i. Displacement of the driver in 1.5 hours = 135 km
ii. Rest for 45 minutes.
iii. Displacement in next 2 hours = 215 km
The direction of motion remains same (east).
Now, total displacement of the driver is,
km.
Rest time is 45 minutes. Converting it to hours, we need to use the conversion factor
hour.
So, 45 minutes in hours is equal to
hours.
Now, total time taken for the complete journey is, ![\Delta t=1.5+\frac{45}{60}+2=1.5+0.75+2=4.25\textrm{ h}](https://tex.z-dn.net/?f=%5CDelta%20t%3D1.5%2B%5Cfrac%7B45%7D%7B60%7D%2B2%3D1.5%2B0.75%2B2%3D4.25%5Ctextrm%7B%20h%7D)
Average velocity is given as:
![v_{avg}=\frac{\textrm{Total displacement}}{Total time}=\frac{350}{4.25}=82.35\textrm{ km/h}](https://tex.z-dn.net/?f=v_%7Bavg%7D%3D%5Cfrac%7B%5Ctextrm%7BTotal%20displacement%7D%7D%7BTotal%20time%7D%3D%5Cfrac%7B350%7D%7B4.25%7D%3D82.35%5Ctextrm%7B%20km%2Fh%7D)
Therefore, the driver's average velocity is 82.35 km/h
Answer:
False.
Explanation:
Backbone Cabling: A system of cabling that connects the equipment rooms and telecommunications rooms.
Horizontal Cabling: The system of cabling that connects telecommunications rooms to individual outlets or work areas on the floor.
Answer:
Radius of the circle will be 2.5 m
Explanation:
We have given velocity of particle moving in the circle v = 5 m/sec
Acceleration of particle in the circle ![a=10m/sec^2](https://tex.z-dn.net/?f=a%3D10m%2Fsec%5E2)
We have to find the radius of the circle
We know that acceleration is given by ![a=\frac{v^2}{r}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv%5E2%7D%7Br%7D)
So ![10=\frac{5^2}{r}](https://tex.z-dn.net/?f=10%3D%5Cfrac%7B5%5E2%7D%7Br%7D)
![r=\frac{25}{10}=2.5m](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B25%7D%7B10%7D%3D2.5m)
So radius of the circle will be 2.5 m
Answer:If kinetic energy increases, so does the thermal energy, and vice versa.
Please brainliest!