A temperature inversion can cause a warm air mass to move over a colder air mass. This traps the colder air mass and prevents

Which kind of covalent bond has unequal sharing of electrons

lutik1710 [3]

Polar.

Polar bonds have unequal sharing electrons while nonpolar, the opposite, has equal sharing electrons. This is a tactic typically used to determine whether or not a compound or element itself is polar or nonpolar.

Hope this helps!

7 0

3 years ago

Read 2 more answers

Which accurately describes nonmetals

Bumek [7]

Answer:

Most nonmetals are solids, but some are gaseous or liquid. All nonmetals are solid unless they bond with a metal.

Explanation:

ANSWER: LOOK IT UP IN YO DICtionary

- williams got dem guns

8 0

3 years ago

Which of the following possess the greatest concentration of hydroxide ions?

jek_recluse [69]

Answer : The correct option is (d) a solution of 0.10 M NaOH

Explanation :

(a) a solution of pH 3.0

First we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-3.0=11$

Now we have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$11=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-11}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-11}M$

(b) a solution of 0.10 M $NH_3$

As we know that 1 mole of $NH_3$ is a weak base. So, in a solution it will not dissociates completely.

So, the $OH^-$ concentration will be less than 0.10 M

(c) a solution with a pOH of 12.

We have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$12=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-12}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-12}M$

(d) a solution of 0.10 M NaOH

As we know that $NaOH$ is a strong base. So, it dissociates to give $Na^+$ ion and $OH^-$ ion.

So, 0.10 M of $NaOH$ in a solution dissociates to give 0.10 M of $Na^+$ ion and 0.10 M of $OH^-$ ion.

Thus, the $OH^-$ concentration is, 0.10 M

(e) a $1\times 10^{-4}M$ solution of $HNO_2$

As we know that 1 mole of $HNO_2$ in a solution dissociates to give 1 mole of $H^+$ ion and 1 mole of $NO_2^-$ ion.

So, $1\times 10^{-4}M$ of $HNO_2$ in a solution dissociates to give $1\times 10^{-4}M$ of $H^+$ ion and $1\times 10^{-4}M$ of $NO_2^-$ ion.

The concentration of $H^+$ ion is $1\times 10^{-4}M$

First we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (1.0\times 10^{-4})$

$pH=4$

Now we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-4=10$

Now we have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$10=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-10}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-10}M$

From this we conclude that, a solution of 0.10 M NaOH possess the greatest concentration of hydroxide ions.

Hence, the correct option is (d)

3 0

4 years ago

Dalton's law of partial pressures states that the total pressure exerted by a mixture of gases is the sum of the pressures exert

Damm [24]

Answer: The given statement is true.

Explanation:

According to the Dalton's law, total pressure of a mixture of gases that do not react with each other is equal to the partial pressure exerted by each gas.

The relationship is as follows.

$p_{total} = \sum_{i=1}^{n} p_{i}$

or, $p_{total} = p_{1} + p_{2} + p_{3} + p_{4} + ......... + p_{n}$

where, $p_{1}, p_{2}, p_{3}$ ....... = partial pressure of individual gases present in the mixture

Also, relation between partial pressure and mole fraction is as follows.

$p_{i} = p_{total} \times x_{i}$

where, $x_{i}$ = mole fraction

Thus, we can conclude that the statement Dalton's law of partial pressures states that the total pressure exerted by a mixture of gases is the sum of the pressures exerted independently by each gas in the mixture, is true.

5 0

3 years ago

Will mark brainliest :) how many moles of a solute is present in 4.00 L of an 8.30 M solution?

andreev551 [17]

The answer is 33.2 moles of a solute is present in 4.00 L of an 8.30 M solution , Option A is correct .

<h3>What is Molarity ?</h3>

Molarity is defined as the amount of solute (in moles)in per litre of solution.

It is also known as molar concentration of a solution , It is expressed in mol/l

$\rm M =\dfrac{moles \;of\; solute}{Volume \;of \;solution} \\\\\\\rm M = \dfrac{n}{V} \\$

We can rearrange this equation to get the number of moles:

n= M * V

The molarity of solution is 8.3 M and the volume given is 4 litres

the moles will be n = 8.30 * 4 = 33.2 moles

Therefore 33.2 moles of a solute is present in 4.00 L of an 8.30 M solution , Option A is correct .

To know more about molarity

brainly.com/question/2817451

#SPJ1

5 0

2 years ago