Question

Etermine the percent yield of the following reaction when 2.80 g of P reacts with excess oxygen. The actual yield of this reaction is determined to by 3.89 g of P2O5.
4 P+5O2→2P2O5

Answer 1

Answer:

Yield = 66.7%

Explanation:

4P + 5O₂ → 2P₂O₅

P: 31 g/mol

O₂: 32 g/mol

P₂O₅: 142 g/mol

31 g P ____ 1 mol

2.80 g P __     x

  x = 0.09 mol P

142 g P₂O₅ ____ 1 mol

3.89 g P₂O₅ ___     y

     y = 0.03 mol P₂O₅

In a 100% yield, 4 mol of P produces 2 mol of P₂O₅. 0.09 of P should, therefore, produce 0.045 mol of P₂O₅.

Yield = (0.03 mol / 0.045 mol) x 100

Yield = 66.7%