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3 years ago

True or false? Pluto is less than 2/3 the size of Earth's moon?

2 answers:

7 0

Pluto<span> has 66% of the diameter of the </span>Earth's moon<span> and 18% of its mass.

So your answer is true

Hope I Helped You!!! :-)

Have A Wonderful Day!!! :-)</span>

never [62]3 years ago

3 0

This is a math problem. To solve this we create a ratio of the radius of Pluto to the Moon.

$\frac{737}{1079}$ showing that Pluto is about 68% the size of the moon. You asked if Pluto was less than $\frac{2}{3}$ or 66%, or less the size of the moon.

68>66 so the answer is False if you are talking about the volume or size of the two.

If you are talking about density, the ratio would be:

$\frac{1.88}{3.34}$ which equals 56% so the answer would be True if you are inquiring about density.

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What 3 weather insturements used to measure weather?

JulijaS [17]

Thermometer for measuring air and sea surface temperature

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8 0

2 years ago

Read 2 more answers

A gas expands and does PV work on its surroundings equal to 319 J. At the same time, it absorbs 136 J of heat from the surroundi

LiRa [457]

Answer:

The change in energy of the gas during the process is $-1.83\times 10^{2}$ joules.

Explanation:

We can represent this process by the First Law of Thermodynamics, in which gas does work on its surroundings and absorbs heat from there to describe its change in energy. In other words:

$Q_{in} - W_{out} = \Delta E$

Where:

$Q_{in}$ - Heat absorbed by the gas, measured in joules.

$W_{out}$ - Work done by the gas, measured in joules.

$\Delta E$ - Change in energy, measured in joules.

If we know that $Q_{in} = 1.36\times 10^{2}\,J$ and $W_{out} = 3.19\times 10^{2}\,J$ , the change in energy of the gas is:

$\Delta E = 1.36\times 10^{2}\,J-3.19\times 10^{2}\,J$

$\Delta E = -1.83\times 10^{2}\,J$

The change in energy of the gas during the process is $-1.83\times 10^{2}$ joules.

3 0

2 years ago

What is latitude 20 degrees north and longitude 65 degrees west?

Marta_Voda [28]

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3 years ago

The mass of a car is 2,400 kg and its momentum is 22,240 kg<br> m/s. What is its velocity?

Crazy boy [7]

Answer:

9.27

Explanation:

6 0

2 years ago

A point charge q1=+5.00nC is at the fixed position x=0, y=0, z=0. You find that you must do 8.10×10−6J of work to bring a second

Maru [420]

The value of the second charge is 1.2 nC.

<h3>Electric potential</h3>

The work done in moving the charge from infinity to the given position is calculated as follows;

W = Eq₂

E = W/q₂

<h3>Magnitude of second charge</h3>

The magnitude of the second charge is determined by applying Coulomb's law.

$E = \frac{kq_2}{r^2} \\\\\frac{kq_2}{r^2} = \frac{W}{q_2} \\\\kq_2^2 = Wr^2\\\\q_2^2 = \frac{Wr^2}{k} \\\\q_2 = \sqrt{\frac{Wr^2}{k} } \\\\q_2 = \sqrt{\frac{(8.1 \times 10^{-6}) \times (0.04)^2}{9\times 10^9} } \\\\q_2 = 1.2 \times 10^{-9} \ C\\\\q_2 = 1.2 \ nC$

Thus, the value of the second charge is 1.2 nC.

Learn more about electric potential here: brainly.com/question/14306881

7 0

2 years ago