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horrorfan [7]
3 years ago
11

Calculate the moment of inertia of a skater given the following information. The skater with arms extended is approximately a cy

linder that is 52.5 kg, has a 0.110-m radius, and has two 0.900-m-long arms which are 3.75 kg each and extend straight out from the cylinder like rods rotated about their ends.
Physics
1 answer:
Bad White [126]3 years ago
4 0

Answer:

The moment of inertia of a skater is : I= 2.343 kgm^{2}

Explanation:

we can use parallel theorem to find the moment of inertia of a skater.

  • Arm extended cylinder mass: M= 52.5 kg
  • Radius: R= 0.110 m
  • Length: L= 0.900 m
  • and m=3.75 kg

I=\frac{1}{2} MR^{2} +[\frac{1}{2} mL^{2} +m(R+\frac{L}{2} )^{2} ]

I=\frac{1}{2} (52.5)(0.110)^{2} +[\frac{1}{12} (3.75)(0.900)^{2} +3.75(0.110+\frac{0.900}{2} )^{2} ]

I=2.343 kgm^{2}

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