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12345 [234]
3 years ago
14

What is the requirement for the photoelectric effect? Select one: a. The incident light must have enough intensity b. The incide

nt light must have a wavelength shorter than visible light c. The incident light must have at least as much energy as the electron work function d. Both b and c
Physics
1 answer:
Softa [21]3 years ago
3 0

Answer:

c. The incident light must have at least as much energy as the electron work function

Explanation:

In photoelectric effect, electrons are emitted from a metal surface when a light ray or photon strikes it. An electron either absorbs one whole photon or it absorbs none. After absorbing a photon, an electron either leaves the surface of metal or dissipate its energy within the metal in such a short time  interval that it has almost no chance to absorb a second photon. An increase in intensity of light source  simply increase the number of photons and thus, the number of electrons, but the energy of electron  remains same. However, increase in frequency of light increases the energy of photons and hence, the

energy of electrons too.

Therefore, the energy of photon decides whether the electron shall be emitted or not. The minimum energy required to eject an electron from the metal surface, i.e. to overcome the  binding force of the nucleus is called ‘Work Function’

Hence, the correct option is:

<u>c. The incident light must have at least as much energy as the electron work function</u>

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The charge density of radius 12.0 cm isgiven by with a = 1.40 μC/m 3 and r ismeasured radially outward from theorigin. What is t
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Answer:

The electric potential of the uniformly charge disk is 1392.1 V

Explanation:

Electric potential, for a uniformly charged disk at a distance A, is given as;

V = \frac{\sigma}{2 \epsilon} [\sqrt{A^2 +R^2} -A]

Where;

σ is the charge density = 1.40 μC/m³

ε is the permittivity of free space = 8.85 x 10⁻¹²

A is the distance above the disk = 40 cm = 0.4 m

R is the radius of the disk = 0.12 m

Substitute in these values into the equation above, we will have

V = \frac{1.4 X 10^{-6}}{2X8,85X10^{-12}}[\sqrt{0.4^2 +0.12^2}-0.4] \\\\V = (79096.05)(0.0176) = 1392.1 V

Therefore, the electric potential of the uniformly charge disk is 1392.1 V

3 0
3 years ago
A force of 500 N acting on an object of 2 kg displaces it by 3 m. Find the work done by the force and the object's final speed a
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7 0
3 years ago
A device called an insolation meter is used to measure the intensity of sunlight. It has an area of 100 cm2 and registers 6.50 W
labwork [276]

Answer:

<h2>650W/m²</h2>

Explanation:

Intensity of the sunlight is expressed as I  = Power/cross sectional area. It is measured in W/m²

Given parameters

Power rating = 6.50Watts

Cross sectional area = 100cm²

Before we calculate the intensity, we need to convert the area to m² first.

100cm² = 10cm * 10cm

SInce 100cm = 1m

10cm = (10/100)m

10cm = 0.1m

100cm² = 0.1m * 0.1m = 0.01m²

Area (in m²) = 0.01m²

Required

Intensity of the sunlight I

I = P/A

I = 6.5/0.01

I = 650W/m²

Hence, the intensity of the sunlight in W/m² is 650W/m²

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3 years ago
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Answer:

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Explanation:

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You measure the velocity of a drag racer that accelerates with constant acceleration. You want to plot the data and determine th
Ivenika [448]

Answer:

a) Linear equation

Explanation:

Definition of acceleration

a=\frac{dv}{dt}\\

if a=constant and we integrate the last equation

v(t)=v_{o}+a*t

So the relation between the time and the velocity is linear. If we plot the velocity in function of time, the plot is a line, and the acceleration is the slope of this line.

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