Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams
Solution : Given,
Volume of solution = 500 ml
Molarity of KOH solution = 0.189 M
Molar mass of KOH = 56 g/mole
Formula used :
Now put all the given values in this formula, we get the mass of solute KOH.
Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams
Michigan v. Tyler was the Supreme court ruling that they violated when
warrantless search was done.
<h3>Michigan v. Tyler case</h3>
The Court of Appeals of the State of Michigan affirmed the conviction for the
exception of a warrantless search only in the case of an arson.
In this case, there was no arson involved which is against the rule of law as
various items (stolen money, illegal weapons, drugs) were only searched for.
This thereby violates the U.S. Supreme Court ruling between Michigan v.
Tyler.
Read more about Michigan v. Tyler case here brainly.com/question/1622038
The patient needs 1000 ml of 5% (w/v) glucose solution
i.e 1000 ml x 5 g/ 100 ml
where the stock solution is 55% (w/v) = 55 g / 100 ml
So, 1000 ml x 5 g / 100 ml = V (ml) x 55 g / 100 ml
V = 1000 x (5 / 100) / (55 / 100) = 5000 / 55 = 90.9 ml
∴ the patient needs 90.9 ml of 55% (w/v) glucose solution
The answer is a. hemoglobin is the molecule that transports oxygen in red blood cells :))))
i hope this is helpful
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Remember....
mass number= atomic number + number of neutrons
If the mass number is 19 and the atomic number is 9, then the number of neutrons is 19-9 which is 10.
