All categories

3 years ago

A neutral atom has an atomic number of 20 and a mass number of 42. How many electrons does the atom have?

Chemistry

2 answers:

Bingel [31]3 years ago

6 0

If we have a neutral atom, then it has the same number protons and neutrons.

The number protons and neutrons for neutral atom shows atomic number.

"A neutral atom has an atomic number of 20" means that atom has 20 protons (that give charge "+ 20" ) and 20 electrons (that give charge "-20").

Answer is 20 electrons.

n200080 [17]3 years ago

3 0

Answer:

The atom with 20 atomic number has 20 electrons.

Explanation:

Atomic number of an atom,Z = 20

Mass number of an atom ,A = 42

Z = Atomic number = Number of proton = Number of electron (neutral atom)

Z = 20

The atom with 20 atomic number has 20 protons.

The atom with 20 atomic number has 20 electrons.

Number of neutrons = A - Z = 42 - 20 = 22

The atom with 20 atomic number has 22 neutrons.

You might be interested in

Calculate the volume of a sample of mercury with a density of 14.6 g/mL and a mass of 1.00 g. The answer is assumed to be in mL.

Darya [45]

Answer:

0.0685 mL

Explanation:

To find the volume of the sample, divide the mass by the density.

(1.00 g)/(14.6 g/mL) = 0.0685 mL

3 0

3 years ago

If a “sample” of pennies contained 75 heads and 25 tails, how many half‐lives would have passed since the “sample” formed. Expla

finlep [7]

..............................

8 0

2 years ago

Which statement is true about a reversible reaction?

vredina [299]

Answer:

The products react to reform the original reactants

E.g. Haber process of ammonia production

6 0

2 years ago

How many ml of 0.5M of HNO3 would be needed to react with 85ml of 0.75M of KOH

olganol [36]

Answer: 127.5ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HNO_3$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is KOH.

We are given:

$n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.75M\\V_2=85mL$

Putting values in above equation, we get:

$1\times 0.5\times V_1=1\times 0.75\times 85\\\\V_1=127.5mL$

Thus 127.5 ml of 0.5M of HNO3 would be needed to react with 85ml of 0.75M of KOH

6 0

3 years ago

Before a new medicine is approved, scientists study the effects the medicine has on different parts of the body. Often, a medici

MissTica

Answer:

different cell specialized in different function

6 0

3 years ago