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nordsb [41]
3 years ago
5

Which of the following is a property of water a. polar molecule b. regulates temperature c.universal solvent d. all of the above

Chemistry
2 answers:
serg [7]3 years ago
8 0
The answer is D. All of the above
Vladimir [108]3 years ago
3 0
The answer is the letter c
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To what volume (in milliliters) should you dilute 100.0 mL of a 5.50 M solution of CaCl2 solution to obtain a 0.950 M solution o
Alexxx [7]

Dilution law is given as:

M_{1}V_{1}=M_{2}V_{2}    (1)

where, M_{1} = molarity of initial concentrated solution.

V_{1} = volume of initial concentrated solution.

M_{2} = molarity of final diluted solution.

tex]V_{2}[/tex] = volume of final diluted solution.

Volume of initial concentrated solution of CaCl_{2}= 100.0 mL

Molarity of initial concentrated solution of CaCl_{2}= 5.50 M

Volume of final diluted solution of CaCl_{2} = 0.950 M

Put the values in formula (1),

5.50 M\times 100.0 mL=0.950 M\times V_{2}

V_{2} =\frac{5.50 M\times 100.0 mL}{0.950 M}

V_{2} =578.9 mL

Hence, final diluted volume of the solution is  578.9 mL.





3 0
4 years ago
Rank and explain how the freezing point of 0.100 m solutions of the following ionic electrolytes compare. List from lowest freez
Elden [556K]

Answer:

The solutions are listed from the lowest freezing point to highest freezing point.

Mg₃(PO₄)₂ -  AlBr₃ - BeBr₂ -  KBr

Explanation:

Colligative property of freezing point, is the freezing point depression.

Formula is:

ΔT = Kf . m . i

Where ΔT = T° freezing pure solvent - T° freezing solution

Kf is the cryoscopic constant

m is molality and i is the Van't Hoff factor (number of ions, dissolved in solution)

In this case, T° freezing pure solvent is 0° because it's water, so the Kf is 1.86 °C/m, and m is 0.1 molal.

The i modifies the T° freezing solution. The four salts, are ionic compounds, so for each case:

BeBr₂  → Be²⁺  +  2Br⁻   i = 3

AlBr₃ →  Al³⁺  + 3Br⁻   i = 4

Mg₃(PO₄)₂  →  3Mg²⁺  +  2PO₄⁻³    i = 5

KBr →  K⁺  +  Br⁻   i = 2

Solution of Mg₃(PO₄)₂ will have the lowest temperature of freezing and the solution of KBr, the highest (always lower, than 0°).

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V125BC [204]

Answer:

sun wind water

Explanation:

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Explanation:

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