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Dmitriy789 [7]
3 years ago
11

A golf ball with m = 46 g is struck a blow which makes an angle of 45o with the horizontal. The drive lands 200 m away on a flat

fairway. If the golf club and ball are in contact for a time of 7 ms, what is the average force of impact?
Physics
1 answer:
AfilCa [17]3 years ago
7 0

Answer:

Average force will be equal to 2908.57 N  

Explanation:

We have given mass of the ball m = 46 gram = 0.046 kg

Let velocity at which ball is projected is u m/sec

Angle at which ball is projected \Theta =45^{\circ}

Range of the ball is given R = 200 m

Range is equal to R=\frac{u^2sin2\Theta }{g}

200=\frac{u^2sin(90^{\circ})}{9.8}

u^2=1960

u = 44.27 m/sec

Change in momentum of the ball is equal to P=mu=0.46\times 44.27=20.36kgm/sec

Time of impact is given dt=7ms=0.007sec

Force is equal to rate of change of momentum

So force F=\frac{dP}{dt}=\frac{20.36}{0.007}=2908.57N

Force will be equal to 2908.57 N

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A current of 4.00 mA flows through a copper wire. The wire has an initial diameter of 4.00 mm which gradually tapers to a diamet
lesya692 [45]

The change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

The given parameters;

  • <em>Current flowing in the wire, I = 4.00 mA</em>
  • <em>Initial diameter of the wire, d₁ = 4 mm = 0.004 m</em>
  • <em>Final diameter of the wire, d₂ = 1 mm = 0.001 m</em>
  • <em>Length of wire, L = 2.00 m</em>
  • <em>Density of electron in the copper, n = 8.5 x 10²⁸ /m³</em>

<em />

The initial area of the copper wire;

A_1 = \frac{\pi d^2}{4} = \frac{\pi \times (0.004)^2}{4} =1.257\times 10^{-5} \ m^2

The final area of the copper wire;

A_2 = \frac{\pi d^2}{4} = \frac{\pi (0.001)^2}{4} = 7.86\times 10^{-7} \ m^2

The initial drift velocity of the electrons is calculated as;

v_d_1 = \frac{I}{nqA_1} \\\\v_d_1 = \frac{4\times 10^{-3} }{8.5\times 10^{28} \times 1.6\times 10^{-19} \times 1.257\times 10^{-5}} \\\\v_d_1 = 2.34 \times 10^{-8} \ m/s

The final drift velocity of the electrons is calculated as;

v_d_2 = \frac{I}{nqA_2} \\\\v_d_2 = \frac{4\times 10^{-3} }{8.5\times 10^{28} \times 1.6\times 10^{-19} \times 7.86\times 10^{-7}} \\\\v_d_2 = 3.74\times 10^{-7}  \ m/s

The change in the mean drift velocity is calculated as;

\Delta v = v_d_2 -v_d_1\\\\\Delta v = 3.74\times 10^{-7} \ m/s \ -\ 2.34 \times 10^{-8} \ m/s = 3.506\times 10^{-7} \ m/s

The time of motion of electrons for the initial wire diameter is calculated as;

t_1 = \frac{L}{v_d_1} \\\\t_1 = \frac{2}{2.34\times 10^{-8}} \\\\t_1 = 8.547\times 10^{7} \ s

The time of motion of electrons for the final wire diameter is calculated as;

t_2 = \frac{L}{v_d_1} \\\\t_2= \frac{2}{3.74 \times 10^{-7}} \\\\t_2 = 5.348 \times 10^{6} \ s

The average acceleration of the electrons is calculated as;

a = \frac{\Delta v}{\Delta t} \\\\a = \frac{3.506 \times 10^{-7} }{(8.547\times 10^7)- (5.348\times 10^6)} \\\\a = 4.38\times 10^{-15} \ m/s^2

Thus, the change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

Learn more here: brainly.com/question/22406248

7 0
2 years ago
A force can give a certain mass a certain acceleration. if i double the force and double the mass, the acceleration of this obje
leva [86]

The acceleration of this item will remain constant if I double the force and double the mass.

<h3>What does acceleration mean ?</h3><h3 />

The rate at which a moving object's speed and direction change over time. When something moves faster or slower, it is considered to be accelerating. Motion on a circle accelerates even while the speed is constant because the direction is always changing.

  • If an object is accelerating and moving in the appropriate direction, it has positive acceleration. The speeding automobile in the first scenario showed positive acceleration. The car is moving forward and accelerating in the same direction as the acceleration.

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6 0
1 year ago
The angular speed of the rotor in a centrifuge increases from 420 to 1420 rad/s in a time of 5.00 s. (a) Obtain the angle throug
9966 [12]

Answer:

a) θ = 2500 radians

b) α = 200 rad/s²

Explanation:

Using equations of motion,

θ = (w - w₀)t/2

θ = angle turned through = ?

w = final angular velocity = 1420 rad/s

w₀ = initial angular velocity = 420

t = time taken = 5s

θ = (1420 - 420) × 5/2 = 2500 rads

Again,

w = w₀ + αt

α = angular accelaration = ?

1420 = 420 + 5α

α = 1000/5 = 200 rad/s²

6 0
3 years ago
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Plz help me! <br><br> How do electromagnetic fields work?
MrMuchimi

Answer:

Electromagnetic field, a property of space caused by the motion of an electric charge. A stationary charge will produce only an electric field in the surrounding space. If the charge is moving, a magnetic field is also produced. An electric field can be produced also by a changing magnetic field.

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3 years ago
Describe the composition of humus and why it is an effective organic fertilizer
kenny6666 [7]

Answer:

soil additive

Explanation:

Soil Additive

The three main components of humus are fulvic acid, humic acid and humin. The spongy nature of humus helps it to trap and hold water, this particular property also helps to aerate the soil as humus expands and contracts with available water.

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2 years ago
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