Answer:
The answer is "Option A".
Explanation:
Series:
![9, 94, 916, 964, 9256, ........](https://tex.z-dn.net/?f=9%2C%2094%2C%20916%2C%20964%2C%209256%2C%20........)
Solving the above series:
![\to 9\\ \to 9(4) =94\\\to 9 (4^2) = 9(16) =916\\\to 9 (4^3) = 9(64) =964\\\to 9 (4^4) = 9(256) =9256\\\to 9 (4^5) = 9(1024) =91024\\\to 9 (4^6) = 9(4096) =94096\\](https://tex.z-dn.net/?f=%5Cto%20%209%5C%5C%20%5Cto%20%209%284%29%20%3D94%5C%5C%5Cto%209%20%284%5E2%29%20%3D%209%2816%29%20%3D916%5C%5C%5Cto%209%20%284%5E3%29%20%3D%209%2864%29%20%3D964%5C%5C%5Cto%209%20%284%5E4%29%20%3D%209%28256%29%20%3D9256%5C%5C%5Cto%209%20%284%5E5%29%20%3D%209%281024%29%20%3D91024%5C%5C%5Cto%209%20%284%5E6%29%20%3D%209%284096%29%20%3D94096%5C%5C)
So, the series is: ![9, 94, 916, 964, 9256, 91024, 94096, .................](https://tex.z-dn.net/?f=9%2C%2094%2C%20916%2C%20964%2C%209256%2C%2091024%2C%2094096%2C%20.................)
Answer:
no
Explanation:
it's not a dead load because when load is put on the pillars it's not fully straining it's been slowly getting to be heavier in that period of time before it falls
Answer:
(A) Maximum voltage will be equal to 333.194 volt
(B) Current will be leading by an angle 54.70
Explanation:
We have given maximum current in the circuit ![i_m=385mA=385\times 10^{-3}A=0.385A](https://tex.z-dn.net/?f=i_m%3D385mA%3D385%5Ctimes%2010%5E%7B-3%7DA%3D0.385A)
Inductance of the inductor ![L=400mH=400\times 10^{-3}h=0.4H](https://tex.z-dn.net/?f=L%3D400mH%3D400%5Ctimes%2010%5E%7B-3%7Dh%3D0.4H)
Capacitance ![C=4.43\mu F=4.43\times 10^{-3}F](https://tex.z-dn.net/?f=C%3D4.43%5Cmu%20F%3D4.43%5Ctimes%2010%5E%7B-3%7DF)
Frequency is given f = 44 Hz
Resistance R = 500 ohm
Inductive reactance will be ![x_l=\omega L=2\times 3.14\times 44\times 0.4=110.528ohm](https://tex.z-dn.net/?f=x_l%3D%5Comega%20L%3D2%5Ctimes%203.14%5Ctimes%2044%5Ctimes%200.4%3D110.528ohm)
Capacitive reactance will be equal to ![X_C=\frac{1}{\omega C}=\frac{1}{2\times 3.14\times 44\times 4.43\times 10^{-6}}=816.82ohm](https://tex.z-dn.net/?f=X_C%3D%5Cfrac%7B1%7D%7B%5Comega%20C%7D%3D%5Cfrac%7B1%7D%7B2%5Ctimes%203.14%5Ctimes%2044%5Ctimes%204.43%5Ctimes%2010%5E%7B-6%7D%7D%3D816.82ohm)
Impedance of the circuit will be ![Z=\sqrt{R^2+(X_C-X_L)^2}=\sqrt{500^2+(816.92-110.52)^2}=865.44ohm](https://tex.z-dn.net/?f=Z%3D%5Csqrt%7BR%5E2%2B%28X_C-X_L%29%5E2%7D%3D%5Csqrt%7B500%5E2%2B%28816.92-110.52%29%5E2%7D%3D865.44ohm)
So maximum voltage will be ![\Delta V_{max}=0.385\times 865.44=333.194volt](https://tex.z-dn.net/?f=%5CDelta%20V_%7Bmax%7D%3D0.385%5Ctimes%20865.44%3D333.194volt)
(B) Phase difference will be given as ![\Phi =tan^{-1}\frac{X_C-X_L}{R}=\frac{816.92-110.52}{500}=54.70](https://tex.z-dn.net/?f=%5CPhi%20%3Dtan%5E%7B-1%7D%5Cfrac%7BX_C-X_L%7D%7BR%7D%3D%5Cfrac%7B816.92-110.52%7D%7B500%7D%3D54.70)
So current will be leading by an angle 54.70
Answer:
250.7mw
Explanation:
Volume of the reservoir = lwh
Length of reservoir = 10km
Width of reservoir = 1km
Height = 100m
Volume = 10x10³x10³x100
= 10⁹m³
Next we find the volume flow rate
= 0.1/100x10⁹x1/3600
= 277.78m³/s
To get the electrical power output developed by the turbine with 92 percent efficiency
= 0.92x1000x9.81x277.78x100
= 250.7MW