The electric field on the surface of an irregularly shaped conductor varies from 66.0 kN/C to 26.0 kN/C. (a) Calculate the local
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Answer:
The velocity is 19.39 m/s
Solution:
As per the question:
Mass, m = 75 kg
Radius, R = 19.2 m
Now,
When the mass is at the top position in the loop, then the necessary centrifugal force is to keep the mass on the path is provided by the gravitational force acting downwards.
where
v = velocity
g = acceleration due to gravity
Answer:
The horizontal distance covered by the firework will be
Explanation:
Let acceleration due to gravity on the planet be g, initial velocity of the firework be u and angle made with the horizontal be ∅.
writing equation of motion in vertical direction:
and
therefore
writing equation of motion in horizontal direction:
therefore the equation becomes
therefore horizontal distance traveled =