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dmitriy555 [2]
3 years ago
8

The electric field on the surface of an irregularly shaped conductor varies from 66.0 kN/C to 26.0 kN/C. (a) Calculate the local

surface charge density at the point on the surface where the radius of curvature of the surface is greatest. nC/m2 (b) Calculate the local surface charge density at the point on the surface where the radius of curvature of the surface is smallest. nC/m2
Physics
1 answer:
Bess [88]3 years ago
4 0

Answer:

Explanation:

We know that at pointed corner of a conductor , charge accumulate ie electric field is  maximum . Ar pointed corner , radius of curvature will be least . That is why charge leakage is greatest at pointed corner of a charged conductor.

a ) Electric field will be 26.0 kN/C at the point where radius of curvature is greatest .

b ) So electric field will be 66 kN /C at the point where radius of curvature is smallest .

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