Average acceleration of the baseball: ![-101 m/s^2](https://tex.z-dn.net/?f=-101%20m%2Fs%5E2)
Explanation:
Since the motion of the baseball is a uniformly accelerated motion, we can use the following suvat equation:
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
where
u is the initial velocity
v is the final velocity
a is the acceleration
s is the displacement of the object
For the baseball in this problem, we have:
u = 2.2 m/s is the initial velocity
v = 0 is the final velocity (it comes to a stop)
s = 24 mm = 0.024 m is the displacement of the ball while decelerating
Therefore, we can solve for a to find the acceleration:
![a=\frac{v^2-u^2}{2s}=\frac{0-2.2^2}{2(0.024)}=-101 m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv%5E2-u%5E2%7D%7B2s%7D%3D%5Cfrac%7B0-2.2%5E2%7D%7B2%280.024%29%7D%3D-101%20m%2Fs%5E2)
where the negative sign means the baseball is slowing down.
Learn more about acceleration:
brainly.com/question/9527152
brainly.com/question/11181826
brainly.com/question/2506873
brainly.com/question/2562700
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