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3 years ago

James and Jill used a battery as a source of electricity to construct

Physics

2 answers:

Pavlova-9 [17]3 years ago

8 0

It would be electromagnet;magnetic

Irina-Kira [14]3 years ago

4 0

electromagnet; magnetic

James and Jill constructed an electromagnet that created magnetic energy that caused the nail to move. The energy transformation is chemical (battery) to electrical to magnetic to mechanical.

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The graph shows two runners participating in a race.

Olin [163]

Answer:

'Daniela had a 5-meter head start, and Leonard caught up to her at 25 meters.'

Explanation:

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6 0

3 years ago

Read 2 more answers

A solid disk has a mass of 162 kg and a radius of 1.30m. This

RideAnS [48]

Answer:

754.3 m

Explanation:

The moment of inertia of the solid disk:

$I = mR^2/2$

Where m is the disk mass and R is the radius of the disk.

$I = 162*1.3^2/2 = 136.89 kgm^2$

The angular kinetic energy of the disk is then:

$E_k = I\omega^2/2 = 136.89 * 18^2/2 = 22176.18 J$

By law of energy conservation, this energy is converted to potential energy to pick up the 3kg block

let g = 9.8 m/s2

$E_p = m_bgh = 22176.18 J$

where $m_b$ = 3 kg is the mass of block

$3*9.8h = 22176.18$

$h = \frac{22176.18}{3*9.8} = 754.3 m$

8 0

3 years ago

Two identical wind-up cars A and B are released. Car B has a 2 kilogram weight strapped to the back of the car. Which will have

koban [17]

Answer:

Car A would have a better average speed

Explanation:

added weight to a object that is self propelled will be slower than a identical object with no added weight

7 0

3 years ago

A projectile is launched diagonally into the air and has a hang time of 24.5 seconds. Approximately how much time is required fo

Rasek [7]

Answer:

$t=12.25\ seconds$

Explanation:

Diagonal Launch

It's referred to as a situation where an object is thrown in free air forming an angle with the horizontal. The object then describes a known path called a parabola, where there are x and y components of the speed, displacement, and acceleration.

The object will eventually reach its maximum height (apex) and then it will return to the height from which it was launched. The equation for the height at any time t is

$x=v_ocos\theta t$

$\displaystyle y=y_o+v_osin\theta \ t-\frac{gt^2}{2}$

Where vo is the magnitude of the initial velocity, $\theta$ is the angle, t is the time and g is the acceleration of gravity

The maximum height the object can reach can be computed as

$\displaystyle t=\frac{v_osin\theta}{g}$

There are two times where the value of y is $y_o$ when t=0 (at launching time) and when it goes back to the same level. We need to find that time t by making $y=y_o$