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Ivan
2 years ago
6

Construct a three-step synthesis of trans-2-pentene from acetylene by dragging the appropriate formulas into the bins. Note that

each bin will hold only one item, and not all of the given reagents or structures will be used. (Me = methyl, CH3; Et = ethyl, CH3CH2.)

Chemistry
1 answer:
Aleks [24]2 years ago
7 0

Answer:

The three-step synthesis of trans-2-pentene from acetylene is as follows.

<u>Step -1:</u> Formation of higher order terminal alkyne on reaction with sodium acetylides with haloalkanes.

<u>Step -2:</u> Formation terminal alkyne to nonterminal alkynes.

<u>Step -3:</u> Formation of trans-pent - 2-pent-ene by reduction.

Explanation:

Synthesis of trans-pent-2-yne from ethyne takes place is mainly a three step synthesis which involves formation of higher order terminal alkyne on reaction with sodium acetylides with haloalkane. Second step involves the further alkylation of terminal alkynes to higher order nonterminal alkynes and the third step involves the formation of trans-2-ene by dissolving reduction method.

The chemical reaction of each step of chemical reactions is as follows.

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Ulleksa [173]

Answer:

<h2>67%</h2>

Explanation:

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6 0
3 years ago
Hydrogen iodide decomposes slowly to H2 and I2 at 600 K. The reaction is second order in HI, and the rate constant is 9.7×10−6M−
Lady bird [3.3K]

Answer : The molarity after a reaction time of 5.00 days is, 0.109 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 9.7\times 10^{-6}M^{-1}s^{-1}

t = time taken  = 5.00 days

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[A]_o = Initial concentration = 0.110 M

Now put all the given values in above equation, we get:

9.7\times 10^{-6}=\frac{1}{5.00}\left (\frac{1}{[A]}-\frac{1}{(0.110)}\right)

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8 0
3 years ago
How do you balance the equation in number one?
AleksAgata [21]
____NaNO3 + ___PbO --> ___Pb(NO3)2 + ___Na[2]O

To balace the eqaution, you need to have the same number of atoms for each element on both the reactant (left) and product (right) side. 

To start off, you wanna know the number of atoms in each element on both sides, so take it apart:

[reactants]        [product]
Na- 1               Na- 2

N- 1               N- 2(it's 2 because the the subscript [2] is outside of the parenthesis)

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Na is not balanced out, so add a coefficient to make it the same on both sides.In this case, multiply by 2: 

2NaNO3

Now Na is balanced, but the N and O are also effected by this, so they also have to be multiplied by 2 and they become: 

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Pb was already balanced so no need to mess with it, just put a 1 where needed (it doesn't change anything). 

Now to put it back together, it will look like this: 

2NaNO3 + 1PbO --> 1Pb(NO3)2 + 1Na[2]O
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3 years ago
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Answer:

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