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Ivan
3 years ago
6

Construct a three-step synthesis of trans-2-pentene from acetylene by dragging the appropriate formulas into the bins. Note that

each bin will hold only one item, and not all of the given reagents or structures will be used. (Me = methyl, CH3; Et = ethyl, CH3CH2.)

Chemistry
1 answer:
Aleks [24]3 years ago
7 0

Answer:

The three-step synthesis of trans-2-pentene from acetylene is as follows.

<u>Step -1:</u> Formation of higher order terminal alkyne on reaction with sodium acetylides with haloalkanes.

<u>Step -2:</u> Formation terminal alkyne to nonterminal alkynes.

<u>Step -3:</u> Formation of trans-pent - 2-pent-ene by reduction.

Explanation:

Synthesis of trans-pent-2-yne from ethyne takes place is mainly a three step synthesis which involves formation of higher order terminal alkyne on reaction with sodium acetylides with haloalkane. Second step involves the further alkylation of terminal alkynes to higher order nonterminal alkynes and the third step involves the formation of trans-2-ene by dissolving reduction method.

The chemical reaction of each step of chemical reactions is as follows.

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Bismuth oxide reacts with carbon to form bismuth metal:
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Answer:

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Explanation:

             Balanced equation: Bi2O3(s) + 3C(s) → 2Bi(s) + 3CO(g)

1st find moles of Bi2O3:

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\hookrightarrow moles = \frac{mass}{Mr}

\hookrightarrow moles = \frac{447}{466}

\hookrightarrow moles = 0.959227

2nd find moles of Bi:

Bi2O3 : 2Bi

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→ 0.959227 : (0.959227)*2

→ 0.959227  : 1.91845

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Therefore 1.92 moles of Bi was produced.

3rd Find moles of 3CO:

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0.959227 : 2.87768

3CO has 2.87768 moles and we know the Mr is 28.

\hookrightarrow mass = moles * Mr

\hookrightarrow mass = 2.87768 * 28

\hookrightarrow mass =80.575 g

Therefore 80.575 grams of CO was produced.

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