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3 years ago

Why is it important to know if a substance is a mixture or pure substance?

Chemistry

1 answer:

laila [671]3 years ago

8 0

Because mixture composition can combust while put compound you have to be careful and know what you mixing

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2. What mass of sodium chloride is produced when chlorine gas reacts with 2.29 grams of sodium iodide? The unbalanced equation i

Damm [24]

Answer:

0.88g

Explanation:

The reaction equation:

2NaI + Cl₂ → 2NaCl + I₂

Given parameters:

Mass of Sodium iodide = 2.29g

Unknown:

Mass of NaCl = ?

Solution:

To solve this problem, we work from the known to the unknown.

First find the number of NaI from the mass given;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of NaI = 23 + 126.9 = 149.9g/mol

Now insert the parameters and solve;

Number of moles = $\frac{2.29}{149.9}$ = 0.015mol

So;

From the balanced reaction equation;

2 moles of NaI produced 2 moles of NaCl

0.015mole of NaI will produce 0.015mole of NaCl

Therefore;

Mass = number of moles x molar mass

Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Now;

Mass of NaCl = 0.015 x 58.5 = 0.88g

8 0

3 years ago

Calculate the percentage of all elements in Fel(OH)3

Vsevolod [243]

Answer: 30.06% is your answer.

I hope this helps.

Stay safe and have a good day :D

7 0

3 years ago

CaCO3(s) ⇄ CaO(s) + CO2(g) 0.100 mol of CaCO3 and 0.100 mol CaO are placed in an 10.0 L evacuated container and heated to 385 K.

Montano1993 [528]

Answer:

The final mass of CaCO3 is 10.68 grams

Explanation:

Step 1: Data given

Number of moles CaCO3 = 0.100 moles

Number of moles CaO = 0.100 moles

Volume = 10.0 L

When equilibrium is reached the pressure of CO2 is 0.220 atm. 0.250 atm of CO2 is added, while keeping the temperature constant

Step 2: The balanced equation

CaCO3(s) <==> CaO(s) + CO2(g)

Step 3: Calculate moles of CO2

n = PV/RT

⇒n = the initial number of moles CO2 = TO BE DETERMINED

⇒P = the pressure of CO2 at theequilibrium = 0.220 atm

⇒V = the volume of the container = 7.0 L

⇒R = the gas constant = 0.08206 L*atm / mol * K

⇒T = the temperature = 385 K

n = 0.220*7.0/(0.08206*385) = 0.0487 (mol)

this is the amount of CaCO3 which has been converted to CaO before pumping-in additional 0.225 atm CO2(g).

Step 4: Calculate moles CaCO3

After adding additional 0.250 atm CO2(g), the equilibrium CO2 pressure is still 0.220 atm. All this additional CO2 would completely convert to CaCO3:

n = PV/RT = 0.250*7.0/(0.08206*385) = 0.0554 moles

The total CaCO3 after equilibrium is reestablished is:

0.100 - 0.0487+ 0.0554 = 0.1067 mol

Step 5: Calculate mass CaCO3

Mass CaCO3 = 0.1067 moles * 100.09 g/mol

Mass CaCO3 = 10.68 grams

The final mass of CaCO3 is 10.68 grams

8 0

3 years ago

ASAP HELP WILL MARK BRAINLIST 7,8,9, and 10

kompoz [17]

7. a. I
8. c. 75 g/ml
9. b. .25g/cm3
10. b. the density decreases

4 0

3 years ago

A 2.00-L sample of was collected over water at a total pressure of 750. torr and 22 °C. When the was dried (water vapor removed)

9966 [12]

Answer : The vapor pressure of water at $22^oC$ is 1.01 atm.

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$

or,

$P_1V_1=P_2V_2$

where,

$P_1$ = initial pressure = ?

$P_2$ = final pressure = 750 torr = 0.987 atm (1 atm = 760 torr)

$V_1$ = initial volume = 1.95 L

$V_2$ = final volume = 2.00 L

Now put all the given values in the above equation, we get:

$P_1\times 1.95L=0.987atm\times 2.00L$

$P_1=1.01atm$

Therefore, the vapor pressure of water at $22^oC$ is 1.01 atm.

7 0

3 years ago