Using the kinematic equation below we can determine the distance traveled if t=2, a=7.4m/s^2. First we must determine the final velocity:

Now we will determine the distance traveled:

Therefore, the drag racer traveled 81.83 meters in 2 seconds.
Answer:
Explanation:
Length, l = 4.32 x 10^4 m
speed, v = 7.07 x 10^3 m/s
magnetic field, B = 5.81 x 10^-5 T
The formula for the motion emf is given by
e = B x v x l
e = 5.81 x 10^-5 x 7.07 x 10^3 x 4.32 x 10^4
e = 17745.1 V
After x seconds, an object will fall

where a is acceleration due to gravity and t is time
so when t=3.3
the distance it will fall is

=53.361m
it will fal 53.361 meters
Answer:
B = 4.059 x 10¹⁵ T
Explanation:
Given,
Number of loop, N = 400
radius of loop, r = 0.65 x 10⁻¹⁵ m
Current, I = 1.05 x 10⁴ A
Magnetic field at the center of the loop


B = 4.059 x 10¹⁵ T