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rusak2 [61]
4 years ago
13

How does the mass of an electron compare to the mass of a proton?

Physics
1 answer:
harina [27]4 years ago
6 0

Answer:

The mass of an electron is only about 1/2000 the mass of a proton.

Explanation:

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A frictionless piston–cylinder device contains 5 kg of nitrogen at 100 kPa and 250 K. Nitrogen is now compressed slowly accordin
Arte-miy333 [17]

Answer:

The work input during this process is -742 kJ

Explanation:

Given;

Initial temperature of nitrogen T₁ = 250 K

final temperature of nitrogen T₂ = 450 K

mass of nitrogen, m = 5 kg

PV^{1.4} = constant

The work input during the process is calculated as;

W = \frac{m*R(T_2-T_1)}{1-n}

where;

R is gas constant = 0.2968 kJ/kgK

substitute given values in above equation.

W = \frac{m*R(T_2-T_1)}{1-n} = \frac{5*0.2968(450-250)}{1-1.4} = -742 \ kJ

Therefore, the work input during this process is -742 kJ

8 0
4 years ago
At a certain moment, a car travelling at 40mph begins braking for a railroad crossing. Assume thatthe acceleration is constant (
egoroff_w [7]

Answer:

Part a)

v_f = 17.88 - (0.15) t

Part b)

d = 1072.8 m

Explanation:

As we know that initial speed of the car is

v = 40 mph

v = 40 \times (\frac{1609}{3600})

v = 17.88 m/s

now we have

v_f = v_i + at

0 = 17.88 + a(120)

a = -0.15 m/s^2

Part a)

As we know that acceleration is constant here

so we have

v_f = v_i + at

v_f = 17.88 - (0.15) t

Part b)

distance moved by the car is given as

d = \frac{v_F + v_i}{2} t

now we have

d = \frac{0 + 17.88}{2}(120)

d = 1072.8 m

3 0
3 years ago
What process is used to release energy in nuclear power plants
Anika [276]
.........Nucler fission.... .
5 0
3 years ago
Read 2 more answers
35. An object of mass m moving at speed v0 strikes an object of mass 2m which had been at rest. The first object bounces backwar
MAVERICK [17]

Answer:

The collision is not elastic. The system increases his kinetic energy m*v₀² times.

Explanation:

Assuming no external forces acting during the collision, total momentum must be conserved.

Considering the information provided, we can write the momentum conservation equation as follows:

m*v₀ = -m*v₀ + 2*m*vf

Solving for vf, we arrive to this somehow surprising result:

vf = v₀ (in the same direction that m was moving before the collision).

In order to determine if the collision was elastic, or not, we need to calculate the kinetic energy of the system before and after the collision:

K₀ = 1/2*m*v₀²

Kf = 1/2*m*v₀² (due to the object of mass m, as the kinetic energy is always positive) + 1/2 (2m) * v₀²

⇒Kf = 1/2*m*v₀² + 1/2 (2m) * v₀² = 3/2*m*v₀²

ΔK = Kf - K₀ = 3/2*m*v₀² - 1/2*m*v₀² = m*v₀²

As there is a net difference between the final and initial kinetic energies, and the total kinetic energy must be conserved in an elastic collision (by definition) we conclude that the collision is not elastic, and the change in the kinetic energy of the system is equal to m*v₀².

5 0
3 years ago
A boat is rocking back and forth in the middle of the ocean. It takes 3 seconds for a wave to pass by before the next wave appea
Amiraneli [1.4K]

The wavelength of the water wave is 15 m.

<h3>What is wavelegth?</h3>

Wavelength is the distance of a complete cycle traveled by a wave.

To calculate the wavelength of the wave, we use the formula below.

Formula:

  • v = λ/T.................Equation 1

Where:

  • v = velocity of wave
  • T = period
  • λ = wavelength.

make λ the subject of the equation

  • λ = vT............... Equation 2

From the question,

Given:

  • v = 5 m/s
  • t = 3 seconds

Substitute these values into equation 2

  • λ = 5(3)
  • λ  = 15 m.

Hence, The wavelength of the water wave is 15 m.
Learn more about wavelength here: brainly.com/question/10750459

8 0
3 years ago
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