Explanation:
it dosent depend on the weights of the items. I'll reach the ground at same time taking as no air friction or restrictions.
i.e
v = u + gt
whte v is final velocity of the object
u is initial velocity of the object
g is acceleration due to gravity and
t is time. thanks
please if found helpful rate brainliest
Question 18: a
question 19: b
question 20: c
Karate class, kicking high and ducking fast makes you much more flexible and you must pay respects to those ou fight with and be intune with yourself to do it right, in other words karate is the answer.
Answer:
The second kinetic energy is 162 J.
Explanation:
Given that,
Mass, ![m_1=15\ g](https://tex.z-dn.net/?f=m_1%3D15%5C%20g)
Velocity, ![v_1=7\ cm/s](https://tex.z-dn.net/?f=v_1%3D7%5C%20cm%2Fs)
Kinetic energy, ![K_1=147\ ergs](https://tex.z-dn.net/?f=K_1%3D147%5C%20ergs)
Mass, ![m_2=10\ g](https://tex.z-dn.net/?f=m_2%3D10%5C%20g)
Velocity, ![v_2=9\ cm/s](https://tex.z-dn.net/?f=v_2%3D9%5C%20cm%2Fs)
We need to find kinetic energy
. Kinetic energy is given by :
![K=\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=K%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
So,
![\dfrac{K_1}{K_2}=\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}\\\\K_2=\dfrac{K_1}{\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}}\\\\K_2=\dfrac{147}{\dfrac{15}{10}\times \dfrac{7^2}{9^2}}\\\\K_2=162\ J](https://tex.z-dn.net/?f=%5Cdfrac%7BK_1%7D%7BK_2%7D%3D%5Cdfrac%7Bm_1%7D%7Bm_2%7D%5Ctimes%20%5Cdfrac%7Bv_1%5E2%7D%7Bv_2%5E2%7D%5C%5C%5C%5CK_2%3D%5Cdfrac%7BK_1%7D%7B%5Cdfrac%7Bm_1%7D%7Bm_2%7D%5Ctimes%20%5Cdfrac%7Bv_1%5E2%7D%7Bv_2%5E2%7D%7D%5C%5C%5C%5CK_2%3D%5Cdfrac%7B147%7D%7B%5Cdfrac%7B15%7D%7B10%7D%5Ctimes%20%5Cdfrac%7B7%5E2%7D%7B9%5E2%7D%7D%5C%5C%5C%5CK_2%3D162%5C%20J)
So, the second kinetic energy is 162 J.
Answer:
A- 20 protons and 20 electrons
Explanation: