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solniwko [45]
3 years ago
15

How to do #10?how to figure it out?

Chemistry
1 answer:
zhannawk [14.2K]3 years ago
4 0

B) is a right answer because molar mass equal molecular atomic mass meaning Ar(Na)=23 and so M(Na)=23 as well.

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How does changing the pressure affect the chemical reaction?
Aleksandr [31]

Answer:

Increasing the pressure on a reaction involving reacting gases increases the rate of reaction. Changing the pressure on a reaction which involves only solids or liquids has no effect on the rate.

Explanation:

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3 years ago
Give an example of a two face mixture and describe how you would separate the substances
shutvik [7]
1.A two face mixture is a type of mixture in which the components of the mixture are in different states of matter. A good example of a two face mixture is carbonated soft drink. Carbonated soft drink is a mixture of carbon dioxide [which is a gas] and water [which is a liquid]. Another example of a two face mixture is the the mixture of iodine and sodium solution.

2. To separate the mixture of iodine and sodium solution the best separation method to use is sublimation.
Sublimation process is used to separate mixtures in which one of the component of the mixture can translate from the solid state to the gaseous state without passing through the liquid state. An example of a solid which can sublime is iodine.
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4 0
3 years ago
Please help me!! Look at the picture to understand the question please!
Romashka-Z-Leto [24]

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C. I

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5 0
2 years ago
SO3 is a covalent compound with no lone pairs on the central S atom. What's the structure of a molecule of SO3? Is an SO3 molecu
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Answer:

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8 0
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I'll mark like brainliest please
Ilya [14]

Answer:

A. 1.75mol of CO2

B. 120g of urea

C. 72g of water

Explanation:

The balanced equation for the reaction is given below:

CO2+ 2NH3 --> H2NCONH2 + H2O

A. From the balanced equation,

1mole of CO2 requires 2moles of NH3.

Therefore, Xmol of CO2 will require 3.5moles of NH3 ie

Xmol of CO2 = 3.5/2 = 1.75mol

B. Let us calculate their molar mass

MM of H2NCONH2 = (2x1)+14+12+16+14+(2x1) = 60g/mol

MM of NH3 = 14 +(3x1) = 17g/mol

But from the balanced equation, 2 moles of NH3 was required. Therefore the mass conc. of NH3 = 2 x 17 = 34g.

Now we calculate the mass of urea produced as follows:

From the equation,

34g of NH3 was required to produce 60g of urea.

Therefore, 68g of NH3 will produce Xg of urea i.e

Xg of urea = (68x60)/34 = 120g

C. From the balanced equation,

2moles of NH3 was required to produced 1mole of H2O.

Therefore, 8 moles of NH3 will produce Xmol of water ie

Xmol of H2O = 8/2 = 4moles

Converting this mole(4moles of water to grams), we have:

MM of H2O = (2x1)+ 16 = 18g/mol

Mass conc. of H20 = 4 x 18 = 72g

6 0
3 years ago
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