Question

Race cars A and B are driving on the same circular racetrack at the same speed of 45.0 m/s. At a given instant car A is on the north side of the track moving eastward and car B is on the south side of the track moving westward. Find the magnitude of the velocity vector of car A relative to car B.

Answer 1

Answer:90 m/s

Explanation:

Given

Speed of both the car is $v=45\ m/s$

Suppose North side and East side as Positive Y and x axis

so Velocity of car A can be written as

$v_a=45\hat{i}$

Velocity of car B is

$v_b=-45\hat{i}$

Velocity of car A relative to car B is given by

$v_{ab}=v_a-v_b$

$v_{ab}=45\hat{i}-(-45\hat{i})$

$v_{ab}=90\hat{i}$

Magnitude of velocity is

$|v_{ab}|=90\ m/s$