Answer:
Explanation:
Given that,
Electric field E=135V/m
Energy stored in 1m³of air=?
The energy stored in an electric field is given as
u = ½ εo E²
Where
U is the energy stored
εo is permissivity and it value is 8.85×10^-12C²/N..m²
And E is the electric field
Then,
U=½×8.85×10^-12×135²
U=8.06×10^-8J/m³
Then, the energy stored in 1m³ of air is 8.06×10^-8 J/m³
Answer:
The pole stores elastic potential energy when the pole is bent because its shape is change from its natural shape and it will want to go back to its original form, just like a spring or stretched elastic material.
Question:
Why did you lie about being in college?
Answer:2 ft/s
Explanation:
Given
Length of Pole is 9 ft
Length of Joe is 3 ft
Joe walks away from Pole at the rate 4 ft/s
Let Joe is x m away from Pole so its shadow length is x'
From Similar triangle concept

3x'=x+x'
x=2x'
and it is given 
Differentiating



Current pulled by these appliances is 10.25 A
Explanation:
- Step 1: Find the total power used by these appliances.
Total power = 240 + 30 + 720 + (2 × 120) = 1230 W
- Step 2: Given voltage is 120 V, find the current by using the formula Power = Voltage × Current
⇒ Current(I) = P/V = 1230/120 = 10.25 A
Answer:

Explanation:
Given:
height above the horizontal form where the ball is hit, 
angle of projectile above the horizontal, 
initial speed of the projectile, 
<u>Firstly we find the </u><u>vertical component of the initial velocity</u><u>:</u>



During the course of ascend in height of the ball when it reaches the maximum height then its vertical component of the velocity becomes zero.
So final vertical velocity during the course of ascend:
Using eq. of motion:
(-ve sign means that the direction of velocity is opposite to the direction of acceleration)

(from the height where it is thrown)
<u>Now we find the time taken to ascend to this height:</u>



<u>Time taken to descent the total height:</u>
- we've total height,


- during the course of descend its initial vertical velocity is zero because it is at the top height, so



<u>Now the total time taken by the ball to hit the ground:</u>


