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Thepotemich [5.8K]

2 years ago

15

Consider the flask apparatus below, which contains 2.00 L of H2 at a pressure of 353 torr and 1.00 L of N2 at an unknown pressur

e. A flask apparatus is composed of two round flasks connected by a single tube fitted with a closed stopcock. The flask on the left has a volume of 2.00 L and contains H2. The flask on the right has a volume of 1.00 L and contains N2. If the total pressure in the flasks is 373 torr after the stopcock is opened, determine the initial pressure of N2 in the 1.00 L flask. (Assume the final volume is 3.00 L.)

2 answers:

Salsk061 [2.6K]2 years ago

7 0

Answer:

Initial pressure of N2 was 413 torr

Explanation:

Given:

- Initial Pressure of H2 = 353 torr

- Initial Volume of H2 = 2 L

- Final Volume of H2 = 3 L

- Total pressure at end = 373 torr

- Iinitial Volume of N2 = 1 L

- Final Volume of N2 = 3 L

Find:

determine the initial pressure of N2 in the 1.00 L flask.

Solution:

- Lets focus on the H2 at first, from pascal's Law we have:

P_1 x V_1 = P_2 x V_2

(353)(2) = (P)(3)

P = 353*2 / 3 = 235.333 torr

- Since the total pressure remains constant the Pressure P of the N2 at the end would be

373 - 235.33 = 137.667 torr

- Now calculate the original P of N2 , again using Pascal's Law:

(P)(1) = (137.667)(3)

P = 137.667*3 = 413 torr

Answer: Initial pressure of N2 was 413 torr

ad-work [718]2 years ago

6 0

Answer:

Explanation:

Given the following ;

Initial volume of Hydrogen = 2.00L

Initial pressure of hydrogen = 353torr

Initial volume of nitrogen = 1.00L

initial pressure of nitrogen = ?

the total pressure in the flask = 373torr

Total volume = 3.00L

From the equation ; ( PV) total = (PV )hydrogen + (PV) nitrogen

(PV) nitrogen = ( PV) total - (PV) hydrogen

= 373 x 3.00 - 353 x 2.00 = 413torr

P(nitrogen) = 413torr = the initial pressure of nitrogen in the 1.00L flask

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