All categories

3 years ago

Please hurry I will be forever grateful <3

Physics

1 answer:

Roman55 [17]3 years ago

7 0

Advandages:

1. Every unit that is connected in a parallel circuit gets equal amount of voltage.

2. It becomes easy to connect or disconnect a new element without affecting the working of other elements.

3. If any fault happened to the circuit, then also the current is able to pass through the circuit through different paths.

Disadvantages:

1. It requires the use of lot of wires.

2. We cannot increase or multiply the voltage in a parallel circuit.

3. Parallel connection fails at the time when it is required to pass exactly same amount of current through the units.

You might be interested in

Two boxes need to be moved into storage. Jamal and Jude each want to move a box. The force of gravity on both the boxes is 50 N.

jolli1 [7]

Answer:

Explanation:

Remark

If both are trying to get the box into storage and they can only use lifting to do it, then Jude won't be able to do it. This assumes they cannot slide the boxes. Jude is not using enough force to overcome gravity so the box will just sit.

On the other hand Jamel is putting enough force to not only lift the box but it will move upwards against gravity. If we ignore that fact, then Jamel will get his box into storage.

Answer: A

4 0

2 years ago

Will someone please help me I only have a couple mins left.

Artyom0805 [142]

Answer:

Okay!! What's the question?

Explanation:

Maybe I can help!

5 0

3 years ago

Jack and Jill are maneuvering a 3100 kg boat near a dock. Initially the boat's position is < 2, 0, 3 > m and its speed is

liraira [26]

Answer:

(a) work done by Jack is -2200J

(b) work done by Jill is 0

Explanation:

Given;

Initially boat's position = < 2, 0, 3 > m

Final boat's position = < 6, 0, 1 > m

change in position = < 4, 0, -2 >

Force exerted by Jack = < -440, 0, 220 > N

Force exerted by Jill = < 170, 0, 340 > N

Part (a) How much work does Jack do?

work done = force x distance

Jack's work = < -440, 0, 220 > N x < 4, 0, -2 > m

= [(-440*4) + (0*0) + (220*-2)]

= -1760 J - 440 J

= -2200J

Part (b) How much work does Jill do?

Jill's work = < 170, 0, 340 > N x < 4, 0, -2> m

= [(170*4) + (0*0) + (340*-2)]

= 680 J - 680 J

= 0

7 0

4 years ago

5.00-kg particle starts from the origin at time zero. Its velocity as a function of time is given by v =6t^2 i + 2t j where v is

otez555 [7]

The concept of derivatives and integrals allows to find the results for the questions are the motion of a particle where the speed depends on time are:

a)the position is: r = 2 t³ i + t² j

b) the position of the body on the y-axis is a parabola and on the x-axis it is a cubic function

c) The acceleration is: a = 12 t i + 2 j

d) the force is: F = 60 t i + 10 j

e) the torque is: τ = 40 t³ k^

f) tha angular momentum is: L = 4t³ - 6 t² k^

g) The kinetic energy is: K = 2 m t² (9t² +1)

h) The power is: P = 2m (36 t³ + 2t)

Kinematics studies the movement of bodies, looking for relationships between position, speed and acceleration.

a) They indicate the function of speed.

v = 6 t² i + 2t j

Ask the function of the position. The velocity is defined by the variation of the position with respect to time

v = $\frac{dr}{dt}$

dr = v dt

we substitute and integrate.

∫ dr = ∫ (6 t² i + 2t j) dt

r - 0 = $6 \frac{t^3 }{3} \ \hat i + 2 \frac{t^2}{2 \ \hat j }$

r = 2 t³ i + t² j

b) The position of the body on the y axis is a parabola and on the x axis it is a cubic function.

c) Acceleration is defined as the change in velocity with time.

$a = \frac{dv}{dt}$

a = $\frac{d}{dt} \ (6t^2 i + 2t j)$

a = 12 t i + 2 j

d) Newton's second law states that force is proportional to mass times the body's acceleration.

F = ma

F = m (12 t i + 2 j)

F = 5 12 t i + 2 j

F = 60 t i + 10 j

e) Torque is the vector product of the force and the distance to the origin.

τ = F x r

The easiest way to write these expressions is to solve for the determinant.

$\tau = \left[\begin{array}{ccc}i&j&k\\F_x&F_y&F_z\\x&y&z\end{array}\right]$

$\tau = \left[\begin{array}{ccc}i&j&k\\60t &10&0\\2t^3 &t^2&0\end{array}\right]$

τ = (60t t² - 2t³ 10) k

τ = 40 t³ k ^

f) Angular momentum

L = r x p

L =rx (mv)

L = m (rxv)

The easiest way to write these expressions is to solve for the determinant.

$\left[\begin{array}{ccc}i&j&k\\2t^3 &t^2&0\\6t^2&2t&0\end{array}\right]$

L = (4t³ - 6 t²) k

g) The kinetic energy is

K = ½ m v²

K = ½ m (6 t² i + 2t j) ²

K = m 18 t⁴ + 2t²

K = 2 m t² (9t² +1)

h) Power is work per unit time

P = $\frac{dW}{dt}$ dW / dt

The relationship between work and kinetic energy

W = ΔK

P = $2m \ \frac{d}{dt} ( 9 t^4 + t^2)$

p = 2m (36 t³ + 2t)

In conclusion with the concept of derivatives and integrals we can find the results for the questions are the motion of a particle where the speed depends on time are:

a) The position is: r = 2 t³ i + t² j

b) The position of the body on the y-axis is a parabola and on the x-axis it is a cubic function

c) The acceleration is: a = 12 t i + 2 j

d) The force is: F = 60 t i + 10 j

e) The torque is: τ = 40 t³ k^

f) The angular momentum is: L = 4t³ - 6 t² k^

g) The kinetic energy is: K = 2 m t² (9t² +1)

h) The power is: P = 2m (36 t³ + 2t)

Learn more here: brainly.com/question/11298125

8 0

2 years ago

Read 2 more answers