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LuckyWell [14K]
3 years ago
9

How can u prove that there is an electric field

Physics
1 answer:
zimovet [89]3 years ago
6 0

Explanation:

By introducing a particle of one positive coulomb between the electric plates, the particle experience a force against the electrostatic forces, proving that it is in an electric field

The force experienced by this particle is known as <em><u>Electric</u></em><em><u> </u></em><em><u>Field</u></em><em><u> </u></em><em><u>Intensity</u></em><em><u> </u></em> denoted by <em><u>E</u></em><em><u> </u></em>and it is given by

k \times \frac{q {}^{2} }{r}

where, k is constant =

9 \times  {10}^{9}

q is the charge magnitude on the particle

r is the separation of the particles

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A student, standing on a scale in an elevator at rest, sees that his weight is 840 n. as the elevator rises, his weight increase
Firlakuza [10]
<span>1) at rest his weight is 840 N

=> 840N = mass * g => mass = 840 N / g = 840 N / 9.8 m/s^2 = 85.7 kg

2) as the elevator rises, his weight increases to 1050 N,

The reading of the scale is the norma force of it over the body of the person.

And the equation for the force is: Net force = mass * acceleration = normal force - weight at rest

=> mass * acceleration = 1050 N - 840 N = 210 N

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3)  when the elevator slows to a stop at the 10th floor, his weight drops to 588 N

=>  mass * acceleration = 588 N - 840 N = - 252 N

=> acceleration = - 252 N / 85.71 kg = - 2.94 m / s^2 (downward)

Answer:

Acceleration at the beginning of the trip 2.45 m/s^2 upward
Acceleration at the end of the trip 2.94 m/s^2 downward
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A 20-cm-long spring is attached to a wall. When pulled horizontally with a force of 100 N, the spring stretches to a length of 2
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the length of stretched spring  in cm is 22

Explanation:

given information:

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if the spring is now suspended from a hook and a 10.2-kg block is attached to the bottom end

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Δx = x2- x1

x2 = Δx + x1

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