The Dalton’s theory is really interesting see you got 6 molecules of water
Answer:
the answer to your question above is D
Answer:
- <em><u>Option A. </u></em><u><em>2KClO₃ → 2KCl + 3O₂</em></u>
Explanation:
There are five basic general types of chemical reactions:
- Synthesis or combination reaction
- Single replacement reactions
- Double replacement reactions
The given reactions are:
- <u>2KClO₃ → 2KCl + 3O₂</u>
Which is, indeed, a decomposition reaction because the reactant, KClO₃, is a single substance that undergoes a reaction in which it yields two new substances, known as products: KCl and O₂.
- <u>4Na + O₂ → 2Na₂O</u> is a synthesis or combination reaction because two reactants, Na and O₂, combine for the formation of one single new product, Na₂O.
- <u>ZnS + 3 O₂ → 2ZnO + 2SO₂ </u>is a single replacement reaction because oxygen is replacing Zn and S in ZnS to form ZnO and plus SO₂.
- <u>2NaBr + CaF₂ → 2NaF + CaBr₂ </u>is a double replacement reaction because two ions (Br⁻ from NaBr and F⁻ from CaF₂) are exchanging places with other two ions (Na⁺ from NaBr and Ca²⁺ from CaF₂) two form two new ionic compounds (NaF and CaBr₂).
Explanation:
It is given that two loads have 0.75 Ampere current each. And, they contain 2500 milli ampere per hour Ni-Cd battery.
As both the loads are connected in parallel. Hence, total current will be calculated as follows.
I = ![I_{1} + I_{2}](https://tex.z-dn.net/?f=I_%7B1%7D%20%2B%20I_%7B2%7D)
= 0.75 A + 0.75 A
= 1.5 A
= ![1.5 A \times \frac{1000 mA}{1 A}](https://tex.z-dn.net/?f=1.5%20A%20%5Ctimes%20%5Cfrac%7B1000%20mA%7D%7B1%20A%7D)
= 1500 mA
Relation between time and capacity of battery is as follows.
Capacity = Current × time (in hour)
therefore, time = ![\frac{Capacity}{Current}](https://tex.z-dn.net/?f=%5Cfrac%7BCapacity%7D%7BCurrent%7D)
= ![\frac{2500 mA. h}{1500 A}](https://tex.z-dn.net/?f=%5Cfrac%7B2500%20mA.%20h%7D%7B1500%20A%7D)
= 1.667 hr
Thus, we can conclude that the battery provide power to the load up to 1.667 hours.
Answer:
Add 10 mL of ethanol into a 100 mL volumetric flask. Final volume of diluted ethanol solution is 100 mL.
Explanation:
We need to use a flask of 100 mL to make a 10 times dilution of the 10 mL of ethanol that we have. To prepare this solution we have to measure with a pipet 10 mL of ethanol and place it into volumetric flask of 100 mL. Then we add destiled water to complete the volume of the final ethanol solution.
Then the final volume of the diluted solution of ethanol will be 100 mL.