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sdas [7]
3 years ago
12

As they move through a DC circuit, electrons collide with ________ in resistors.

Physics
1 answer:
KengaRu [80]3 years ago
6 0

Answer:

idk man

Explanation:

i am suffereing from this i am in Mr.GoofFreinds class and this quiz is hard.

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A box is pushed to the right with a force of 5N and at the same time it is pushed with a force of 3.6 N to the left. If the box
Aliun [14]

Answer: a= 0.175 m/s²

Explanation: To solve for acceleration we will use Newton's Second Law of Motion which is F=ma. Since there are multiple forces acting on the object, we need to summate the forces involved. Derive to find acceleration.

a= F/m

= 5 N - 3.6 N / 8 kg

= 0.175 m/s²

8 0
3 years ago
A student pushes a 50-N box across the floor a distance of 15 m. How much work was done to move the box?
irinina [24]

Answer:750

Explanation:

50 times 15

4 0
3 years ago
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Question 2 (ID=81813)
zaharov [31]

Answer:

The answer is B

Explanation:

5/2=2.5

2.5x2=5

Hope this helps ik its kinda confusing lol

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3 years ago
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Buco novia de 15n de edad
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3 years ago
The length of a certain wire is kept same while its radius is doubled. what is the new resistivity of this wire?
anastassius [24]
The text does not specify whether the resistance R of the wire must be kept the same or not: here I assume R must be kept the same.

The relationship between the resistance and the resistivity of a wire is
\rho =  \frac{AR}{L}
where
\rho is the resistivity
A is the cross-sectional area
R is the resistance
L is the wire length

the cross-sectional area is given by
A=\pi r^2
where r is the radius of the wire. Substituting in the previous equation ,we find
\rho =  \frac{\pi r^2 R}{L}

For the new wire, the length L is kept the same (L'=L) while the radius is doubled (r'=2r), so the new resistivity is
\rho' =  \frac{\pi r'^2 R}{L'}= \frac{\pi (2r)^2 R}{L}=4  \frac{\pi r^2 R}{L}   = 4 \rho
Therefore, the new resistivity must be 4 times the original one.
5 0
3 years ago
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