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3 years ago

13

In your own words, explain why light can travel with or without a medium

1 answer:

Darya [45]3 years ago

7 0

I'm not really sure if it's completely right but I was taught that light can travel without a medium because light is composed of quanta called photons, and since it is a property of photons that they don't require a medium of transmission
( sorry if that doesn't make sense )

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If the small piston has an area of .004 square

denpristay [2]

The magnitude of the pressure : P = 56,250 N/m

<h3>Further explanation</h3>

Given

Area of 0.004 m²

Force 225 N

Required

the magnitude of the pressure

Solution

Pressure = force exerted per unit of surface area(perpendicular)

Can be formulated :

P = F/A

Input the value :

P = 225 N / 0.004 m

P = 56,250 N/m

8 0

2 years ago

A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 50.4 m/s and returns the shot with the ball

lora16 [44]

Explanation:

It is given that,

Mass of the ball, m = 0.06 kg

Initial speed of the ball, u = 50.4 m/s

Final speed of the ball, v = -37 m/s (As it returns)

(a) Let J is the magnitude of the impulse delivered to the ball by the racket. It can be calculated as the change in momentum as :

$J=m(v-u)$

$J=0.06\times (-37-(50.4))$

J = -5.24 kg-m/s

(b) Let W is the work done by the racket on the ball. It can be calculated as the change in kinetic energy of the object.

$W=\dfrac{1}{2}m(v^2-u^2)$

$W=\dfrac{1}{2}\times 0.06\times ((-37)^2-(50.4)^2)$

W = -35.1348 Joules

Hence, this is the required solution.

6 0

3 years ago

Which statement about vectors is true?

ycow [4]

Answer:

D. Vectors are quantities described by both magnitude and direction.

Explanation

4 0

2 years ago

Read 2 more answers

What is the sound intensity level in decibels? Use the usual reference level of I0 = 1.0×10−12 W/m2.

jek_recluse [69]

Answer:

L = 130 decibels

Explanation:

The computation of the sound intensity level in decibels is shown below:

According to the question, data provided is as follows

I = sound intensity = 10 W/m^2

I0 = reference level = $1 \times 10-12 W/m^2$

Now

Intensity level ( or Loudness)is

$L = log10 \frac{I}{10}$

$L = log10 \frac{10}{1\times 10^{-12}}$

$L = log10 \times 1013$

$= 13 \times 1 ( log10(10) = 1)$

Therefore

L = 13 bel

And as we know that

1 bel = 10 decibels

So,

The Sound intensity level is

L = 130 decibels

5 0

3 years ago

Calculate the index of refraction for a medium in which the speed of light is 2.1x 108 m/s. The speed of light in vacuum is 3x10

strojnjashka [21]

Answer:

n = 1.42

Explanation:

The refractive index for a medium is given by the ratio of the speed of light in vacuum to the speed of light in a medium.

$n=\dfrac{c}{v}\\\\n=\dfrac{3\times 10^8}{2.1\times 10^8}\\\\n = 1.42$

So, the refractive index of the medium is 1.42.

5 0

3 years ago