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Lerok [7]
3 years ago
14

A 0.14-kg baseball is moving at 41 m/s. A 0.058-kg tennis ball is moving at 67 m/s. Which of the two balls has higher kinetic en

ergy?
Physics
1 answer:
lbvjy [14]3 years ago
6 0

Answer:

The kinetic energy of tennis ball is higher than that of baseball.

Explanation:

mass of baseball m_{b} = 0.14 kg

velocity of baseball v_{b} = 41 m/s

mass of tennis ball m_{t}  = 0.058 kg

velocity of tennis ball v_{t}= 67 m/s

To find: the kinetic energy of baseball KE_{b} and tennis ball KE_{t}

We know that the kinetic energy is given by the equation,

KE = \frac{mv^{2}}{2}

the kinetic energy of baseball KE_{b} = \frac{m_{b}v_{b}  ^{2}}{2}

                                                           = \frac{0.14 * 41^{2}}{2}

                                                           = 117.67 J

the kinetic energy of tennis ball KE_{t} = \frac{m_{t}v_{t}  ^{2}}{2}

                                                             = \frac{0.058 * 67^{2}}{2}

                                                             = 130.181 J

Hence KE_{t} > KE_{b}, the kinetic energy of tennis ball is higher than that of baseball

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ou have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 660.0 kg and was trav
Montano1993 [528]

Answer:

    vₐ₀ = 29.56 m / s

Explanation:

In this exercise the initial velocity of car A is asked, to solve it we must work in parts

* The first with the conservation of the moment

* the second using energy conservation

let's start with the second part

we must use the relationship between work and kinetic energy

             W = ΔK                             (1)

for this part the mass is

             M = mₐ + m_b

the final velocity is zero, the initial velocity is v

friction force work is

              W = - fr x

the negative sign e because the friction forces always oppose the movement

we write Newton's second law for the y-axis

              N -W = 0

              N = W = Mg

friction forces have the expression

              fr =μ N

              fr = μ M g

we substitute in 1

               -μ M g x = 0 - ½ M v²

             v² = 2 μ g x

let's calculate

              v² = 2  0.750  9.8  6.00

              v = ra 88.5

              v = 9.39 m / s

Now we can work on the conservation of the moment, for this part we define a system formed by the two cars, so that the forces during the collision are internal and therefore the tsunami is preserved.

Initial instant. Before the crash

         p₀ = + mₐ vₐ₀ - m_b v_{bo}

instant fianl. Right after the crash, but the cars are still not moving

         p_f = (mₐ + m_b) v

         p₀ = p_f

         + mₐ vₐ₀ - m_b v_{bo} = (mₐ + m_b) v

           

         mₐ vₐ₀ = (mₐ + m_b) v + m_b v_{bo}

let's reduce to the SI system

          v_{bo} = 64.0 km / h (1000m / 1km) (1h / 3600s) = 17.778 m / s

let's calculate

         660 vₐ₀ = (660 +490) 9.39 + 490 17.778

         vₐ₀ = 19509.72 / 660

         vₐ₀ = 29.56 m / s

we can see that car A goes much faster than vehicle B

5 0
3 years ago
(b) The output current of the generator is 2.0A. The output potential difference (p.d.) of the
Luden [163]

Answer:

P = 22 watts

Explanation:

Given that,

The output power of the generator = 2 a

The output potential difference = 11 V

We need to find the output power of the generator. The formula for the output power is given by :

P=V\times I\\\\P=11\times 2\\\\P=22\ W

So, the output power of the generator is equal to 22 Watts.

8 0
3 years ago
A 1500 kg tractor pulls a 750 kg trailer north and applies a 2250 N force on it. What is the force on the tractor?
Masja [62]

Answer:

law of Action and Reaction     F = 2250 N

Explanation:

The tractor and the trailer are two bodies that interact, therefore, by the law of Action and Reaction, the force that one applies on the other is equal to the force that the second body (trailer) applies on the first (tractor), but with opposite direction

          F = 2250 N

directed from trailer to tractor

3 0
3 years ago
What family of elements has 7 valence electrons?
ivann1987 [24]
Group 17 (VII) (halogens)
4 0
3 years ago
Read 2 more answers
A car accelerates from 0 to 30m/s in 3s. Calculate its acceleration
creativ13 [48]

Answer:

10 m/s2

Explanation:

a = v- u/ t

=>a = 30-0 / 3

= 30/ 3

= 10m/s2

8 0
3 years ago
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