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Lerok [7]
3 years ago
14

A 0.14-kg baseball is moving at 41 m/s. A 0.058-kg tennis ball is moving at 67 m/s. Which of the two balls has higher kinetic en

ergy?
Physics
1 answer:
lbvjy [14]3 years ago
6 0

Answer:

The kinetic energy of tennis ball is higher than that of baseball.

Explanation:

mass of baseball m_{b} = 0.14 kg

velocity of baseball v_{b} = 41 m/s

mass of tennis ball m_{t}  = 0.058 kg

velocity of tennis ball v_{t}= 67 m/s

To find: the kinetic energy of baseball KE_{b} and tennis ball KE_{t}

We know that the kinetic energy is given by the equation,

KE = \frac{mv^{2}}{2}

the kinetic energy of baseball KE_{b} = \frac{m_{b}v_{b}  ^{2}}{2}

                                                           = \frac{0.14 * 41^{2}}{2}

                                                           = 117.67 J

the kinetic energy of tennis ball KE_{t} = \frac{m_{t}v_{t}  ^{2}}{2}

                                                             = \frac{0.058 * 67^{2}}{2}

                                                             = 130.181 J

Hence KE_{t} > KE_{b}, the kinetic energy of tennis ball is higher than that of baseball

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Answer:

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Explanation:

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3 0
4 years ago
How much power is needed to lift the 200-N object to a height of 4 m in 4 s?
Vitek1552 [10]

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Explanation:

Given that,

power = ?

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height = 4 m

Time = 4 s

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i.e Power = work / time

(since work = force x distance, and weight is the force acting on the object due to gravity)

Then, Power = (weight x distance) / time

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3 0
3 years ago
I have a bottle of gas, the bottle can expand and contract. Initially the gas is at 1 kpa of pressure and a volume of 1 Liter, a
drek231 [11]

Answer:

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Explanation:

This problem can be solved using the equation of state:

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where,

P₁ = initial pressure = 1 KPa

P₂ = final pressure = ?

V₁ = initial Volume = 1 liter

V₂ = final volume = 1.1 liter

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T₂ = final temperature = 390 k

Therefore,

\frac{(1\ kPa)(1\ liter)}{290\ k} =\frac{(P_2)(1.1\ liter)}{390\ k}\\\\P_2= \frac{(1\ kPa)(1\ liter)(390\ k)}{(290\ k)(1.1\ liter)}

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Ear barotrauma is a medical condition that describes discomfort in the ear which is caused by pressure differences in the inner and outer ear drum.

Usually, the air pressure in the middle ear is the same as the air pressure in the throat and outside the body.

When we swallow, the eustachian tube opens up and air flows out of and into the middle ear, this balances the pressure. But if the eustachian tube is blocked, the air pressure in the throat and outer body become different from the air pressure in the middle ear.

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