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valkas [14]
3 years ago
8

You need to make a spring scale to measure the mass of objects hung from it. You want each 2.1 cm length along the scale to corr

espond to a mass difference of 0.10 kg. What should be the value of the spring constant?
Physics
2 answers:
pashok25 [27]3 years ago
7 0

Answer:

k = 46.67 N/m

Explanation:

given,

mass, m = 0.10 Kg

Length, x = 2.1 cm = 0.021 m

spring constant, k = ?

we know,

spring force

F = k x

and also

F = m g

computing both the equation

k x = m g

k = \dfrac{mg}{x}

k = \dfrac{0.1\times 9.8}{0.021}

k = 46.67 N/m

Spring constant for the spring is equal to k = 46.67 N/m

Gennadij [26K]3 years ago
4 0

Answer:

46.67 N/m

Explanation:

mass, m = 0.1 kg

distance, y = 2.1 cm = 0.021 m

Let K be the spring constant.

F = mg = Ky

0.1 x 9.8 = K x 0.021

K = 46.67 N/m

Thus, the spring constant of the spring is 46.67 N/m.

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A real heat engine operates between temperatures tc and th. during a certain time, an amount qc of heat is released to the cold
tino4ka555 [31]

q_{c} = Heat released to cold reservoir

q_{h} = Heat released to hot reservoir

W_{max} = maximum amount of work

t_{c} = temperature of cold reservoir

t_{h} = temperature of hot reservoir

we know that

\frac{q_{c}}{q_{h}}=\frac{t_{c}}{t_{h}}

q_{h} = (\frac{t_{h}}{t_{c}})q_{c}                                eq-1

maximum work is given as

W_{max} = q_{h} - q_{c}

using eq-1

W_{max} =  (\frac{t_{h}}{t_{c}})q_{c} - q_{c}



6 0
3 years ago
I need help with the graphs
Viefleur [7K]
For heating Solid, Liquid, Gas and for cooling the opposite Gas, Liquid, Solid
8 0
3 years ago
Hey! anybody knows the answer then help me i will mark your answer!!!
Volgvan

10/9

Explanation:

option 2 is the correct answer

8 0
2 years ago
Calculate the volume of this regular solid.
Nataly [62]

Answer:

V = 42.41cm^3

Explanation:

In order to calculate the volume of the solid, you use the following formula:

V=\frac{1}{3}\pi r^2 h

where

r: radius of the circular base of the cone = 3 cm

h: height from the circular base to the peak of the cone = 4.5 cm

You replace the values of r and h in the formula for the volume V:

V=\frac{1}{3}\pi(3cm)^2(4.5)=42.411cm^3\approx42.41cm^3

hence, the volume of the solid is 42.41 cm^3

5 0
2 years ago
A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a rope that goes over an ideal pulley. If the masses are
irga5000 [103]

Answer:

The time taken will be 0.553 seconds.

Explanation:

We should start off by finding the force exerted by the rope on the 3kg weight in this case.

Weight of 5kg mass = 5 * 9.81 = 49.05 N

Weight of 3kg mass = 3 * 9.81 = 29.43 N

The force acting upward on the 3kg mass will equal the weight of the 5kg mass. Thus the resultant force acting on the 3kg mass is:

Total force = 49.05 - 29.43 = 19.62 N (upwards)

We can now find the acceleration:

F = m * a

19.62 = 3 * a

a = 6.54 m/s^2

We now use the following equation of motion to get the time taken to travel 1 meter:

s=u*t+\frac{1}{2} (a*t^2)

1=0*t+\frac{1}{2} (6.54*t^2)

t = 0.553 seconds

4 0
3 years ago
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