The angular speed remained constant after twelve turns at 11 rad/s.
Explanation:
As per the Newtons equation of motion, the final velocity can be determined by using the below equation, provided ,the displacement and acceleration with initial velocity is given.

Since, the present case follows circular motion, the displacement will be equal to angular displacement. And the velocity is equal to angular velocity.
As the car revolves complete twelve turns, then the displacement will be zero, since the final position is equal to the initial position.
So,

Thus, the angular speed remained constant after twelve turns at 11 rad/s.
The velocity of the target and arrow after collision is 6.67m/s
<u>Explanation:</u>
Given:
Mass of arrow, mₐ = 415g
Speed of arrow, vₐ = 68.5m/s
Mass of the target, mₓ = 3.3kg = 3300g
speed of the target, vₓ = -1.1m/s (Because the target moves in opposite direction
Velocity of the target and arrow after collision, vₙ = ?
Applying the conservation of momentum,
mₐvₐ + mₓvₓ = (mₐ+mₓ) vₙ
415 X 68.5 + 3300 X -1.1 = (415+3300) X vₙ
28427.5 - 3630 = 3715 X vₙ
24797.5 = 3715 X vₙ
vₙ = 6.67m/s
Therefore, the velocity of the target and arrow after collision is 6.67m/s
Boyle's law<span> talks about the relationship </span>between<span> pressure and volume (high pressure = low volume, and vice-versa), while </span>Charles's law<span> talks about the relationship </span>between<span> volume and temperature (high temperature = high volume, and vice-versa).</span>
The correct answer is a I hope that helped enjoy the rest of your weekend