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notsponge [240]
4 years ago
9

A soccer ball is kicked; it comes to rest after rolling through the grass. Why is this not considered a violation of Newton's Fi

rst Law?
Physics
2 answers:
julsineya [31]4 years ago
7 0

Newton's law states that objects at rest/motion will remain at rest/motion "UNLESS" a force is acted upon it.

So the soccer ball got kicked, and then came to rest. This doesn't state that the soccer ball was still rolling when the force of someone's foot kicked the ball.

Inessa [10]4 years ago
7 0

The ball was put in motion by the kick (an external force). The fact that it failed to continue in a uniform motion is due to (again) an external force acting on it. This time it is the force of <em>friction</em>. The ball rolling through grass hitting small obstacles can be, in aggregate, represented by a force acting against its direction of motion. This force exists until the ball stops. So, Newton's doing fine.

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A car traveling west in a straight line on a highway decreases its speed from 30 meters per second to 23 meters per second in 2
garik1379 [7]
U1= 30m/s
u2= 23m/s
t=2s
a=(u2-u1)/t
a=-7/2=-3.5 m/s^2
6 0
3 years ago
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Which is an example of conduction?
densk [106]

Answer:

Touching the stove and getting burned, ice melting in your hand

Explanation:

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3 years ago
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7.22 Ignoring reflection at the air–water boundary, if the amplitude of a 1 GHz incident wave in air is 20 V/m at the water surf
Serga [27]

Answer:

z = 0.8 (approx)

Explanation:

given,

Amplitude of 1 GHz incident wave in air = 20 V/m

Water has,

μr = 1

at 1 GHz, r = 80 and σ = 1 S/m.

depth of water when amplitude is down to  1 μV/m

Intrinsic impedance of air = 120 π  Ω

Intrinsic impedance of  water = \dfrac{120\pi}{\epsilon_r}

Using equation to solve the problem

  E(z) = E_0 e^{-\alpha\ z}

E(z) is the amplitude under water at z depth

E_o is the amplitude of wave on the surface of water

z is the depth under water

\alpha = \dfrac{\sigma}{2}\sqrt{\dfrac{(120\pi)^2}{\Epsilon_r}}

\alpha = \dfrac{1}{2}\sqrt{\dfrac{(120\pi)^2}{80}}

\alpha =21.07\ Np/m

now ,

  1 \times 10^{-6} = 20 e^{-21.07\times z}

  e^{21.07\times z}= 20\times 10^{6}

taking ln both side

21.07 x z = 16.81

z = 0.797

z = 0.8 (approx)

5 0
4 years ago
A microphone is located on the line connecting two speakers that are 0.513 m apart and oscillating in phase. The microphone is 1
pantera1 [17]

Answer:

frequency 1 = 334.30 Hz

frequency 2 = 1002.92 Hz

Explanation:

Given data

speaker distance y = 0.513 m

microphone distance D = 1.80 m

to find out

lowest two frequencies

solution

we know velocity of sound is 343 m/s

so we consider point x

so at 1st speaker distance from x   = D + (y/2)

1st speaker distance from x   = 1.80 + (0.513/2) = 2.0565 m   .....1

and

at 2nd speaker distance from x   = D - (y/2)

2nd speaker distance from x   = 1.80 - (0.513/2) = 1.5435 m     .........2

so destructive interference from 1 and 2  we know

1st - 2nd = ( m + 0.5 ) wavelength

2.0565 m - 1.5435 m = (  0+ 0.5) wavelength

wavelength  = 1.026 m

so here 1st min frequency will be

frequency 1 = velocity of sound / wavelength

frequency 1 = 343 / 1.026 =334.30 Hz

and

2nd  min frequency will be

frequency 2 =

2.0565 m - 1.5435 m = (  1 + 0.5) wavelength

wavelength  = 0.342 m

frequency 2 =  velocity of sound / wavelength

frequency 2 = 343 / 0.342 = 1002.92 Hz

7 0
3 years ago
If you were to travel from the equator to the higher latitudes (near either pole) on Saturn, the differential rotation would cau
Dmitrij [34]

Answer:

Saturn's differential rotation will cause the length of a day measures to be longer by 0.4 hours

Explanation:

Differential rotation occurs due to the difference in angular velocities of an object as we move along the latitude of the or as we move into different depth of the object, indicating the observed object is in a fluid form

Saturn made almost completely of gas and has differential motion given as follows

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Rotation at high altitude = 10 hours 38 minutes

Therefore;

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The differential rotation = 24 minutes = 24 minutes × 1 hour/(60 minutes) = 0.4 hours

The differential rotation = 0.4 hours

Therefore, the measured day at the higher altitude will be 0.4 longer than at the equator.

8 0
3 years ago
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